blocks|key|2329265|text|这是因为在Python3中，range会返回一个range对象。把它放在list中，让它做你想做的事情：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2329266|>>>+Var1+=+range(10,+50)
>>>+print(list(Var1))
[10,+11,+12,+13,+14,+15,+16,+17,+18,+19,+20,+21,+22,+23,+24,+25,+26,+27,+28,+29,+30,+31,++
32,+33,+34,+35,+36,+37,+38,+39,+40,+41,+42,+43,+44,+45,+46,+47,+48,+49]
>>>|code-block|syntax|javascript|2329267|entityMap^0|E|5|10|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Thats because <code>range</code> returns a range object in Python 3. Put it in <code>list</code> to make it do what you want:

<pre><code>&gt;&gt;&gt; Var1 = range(10, 50)
&gt;&gt;&gt; print(list(Var1))
[10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 
32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49]
&gt;&gt;&gt;
</code></pre>

blocks|key|2329277|text|这一点在Python3.0中有所改变。您可以在Python2.7中重新创建类似的函数，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2329278|def+range(low,+high=None):
++if+high+==+None:
++++low,+high+=+0,+low
++i+=+low
++while+i+<+high:
++++yield+i
++++i+%2B=+1|code-block|syntax|javascript|2329279|这样做的好处是，在使用列表之前不必创建列表。|2329280|for+i+in+range(1,999999):
++text+=+raw_input("{}:+".format(i))
++print+"You+said+{}".format(text)|2329281|它是这样工作的：|2329282|1:+something
You+said+something
2:+something+else
You+said+something+else
3:+another+thing
You+said+another+thing|2329283|在Python3.x中，如果我们永远不会到达循环的末尾(999997次迭代)，它将永远不会计算所有的项。在Python2.7中，它必须首先构建整个范围。在一些旧的Python实现中，这是非常慢的。|2329284|entityMap^0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

This is something that was changed in Python 3.0. You could recreate a similar function in Python 2.7 like so,

<pre><code>def range(low, high=None):
 if high == None:
 low, high = 0, low
 i = low
 while i &lt; high:
 yield i
 i += 1
</code></pre>

The benefit of this, is that the list doesn't have to be created before its used. 

<pre><code>for i in range(1,999999):
 text = raw_input("{}: ".format(i))
 print "You said {}".format(text)
</code></pre>

Which works like this:

<pre><code>1: something
You said something
2: something else
You said something else
3: another thing
You said another thing
</code></pre>

In Python 3.X, if we never get to the end of our loop (999997 iterations), it will never calculate all of the items. In Python 2.7 it has to build the entire range initially. In some older Python implementations, this was very slow.

blocks|key|4646460|text|您可能应该了解一些幕后发生的事情。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4646461|在Python3中，range返回一个range对象，而不是您所期望的列表。(注：python+3的range是python+2的xrange)|offset|length|style|CODE|4646462|#python+2
>>>+type(range(5))
<type+'list'>

#python+3
>>>+type(range(5))
<class+'range'>|code-block|syntax|javascript|4646463|那是什么意思？range对象只是一个迭代器--您需要强制它迭代以获取其内容。这对新生儿来说可能听起来很烦人，但事实证明它是非常有用的。|4646464|>>>+import+sys
>>>+sys.getsizeof(range(5))
24
>>>+sys.getsizeof(range(1000000))
24|4646465|这样做的最大优点是:恒定(微小)的内存占用。出于这个原因，标准库中的许多东西都只是返回迭代器。权衡之处在于，如果您只是想查看迭代范围，则必须强制它进行迭代。要做到这一点，最常见的用法是list(range(n))。还有理解、for循环和更深奥的方法。迭代器是学习python的一个重要部分，所以要习惯它们！|4646466|entityMap^0|0|A|5|J|5|1E|5|1T|6|0|0|0|0|2K|E|34|3|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|V|8|@$D|W|E|X|F|G]|$D|Y|E|Z|F|G]|$D|10|E|11|F|G]|$D|12|E|13|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|14|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|15|8|@]|9|@]|A|$]]|$1|O|3|P|5|J|7|16|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|17|8|@$D|18|E|19|F|G]|$D|1A|E|1B|F|G]]|9|@]|A|$]]|$1|S|3|-4|5|6|7|1C|8|@]|9|@]|A|$]]]|T|$]]

You should probably understand a bit of what is happening under the hood.

In python 3, <code>range</code> returns a <code>range</code> object, not a list like you may have been expecting. (n.b. python 3's <code>range</code> is python 2's <code>xrange</code>)

<pre><code>#python 2
&gt;&gt;&gt; type(range(5))
&lt;type 'list'&gt;

#python 3
&gt;&gt;&gt; type(range(5))
&lt;class 'range'&gt;
</code></pre>

What does that mean? Well, the range object is simply an iterator - you need to force it to iterate to get its contents. That may sound annoying to the neonate, but it turns out to be quite useful.

<pre><code>&gt;&gt;&gt; import sys
&gt;&gt;&gt; sys.getsizeof(range(5))
24
&gt;&gt;&gt; sys.getsizeof(range(1000000))
24
</code></pre>

The biggest advantage of doing things this way: constant (tiny) memory footprint. For this reason, many things in the standard library simply return iterators. The tradeoff is that if you simply want to see the iterated range, you have to force it to iterate. The most common idiom to do that is <code>list(range(n))</code>. There's also comprehensions, <code>for</code> loops, and more esoteric methods. Iterators are a huge part of learning python so get used to them!

Whenever I try to assign a range to a variable like so:

<pre><code>Var1 = range(10, 50)
</code></pre>

Then try to print the variable:

<pre><code>Var1 = range(10, 50)
print(Var1)
</code></pre>

It simply prints 'range(10, 50)' instead of all the numbers in the list. Why is this?

Assign a range to a variable (Python)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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每当我尝试像这样给变量分配一个范围时：Var1 = range(10, 50)然后尝试打印变量：Var1 = range(10, 50)print(Var1)它只是打印“range(10，50)”，而不是列表中的所有数字。为什么会这样呢？

问将范围分配给变量(Python)
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