blocks|key|4547514|text|if+(numerator.GetType()+==+typeof(int))
{
++++...
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4547515|typeof+(MSDN)|unstyled|offset|length|4547516|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/58918ffs%2528v=VS.100%2529.aspx^0|0|0|D|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>if (numerator.GetType() == typeof(int))
{
 ...
}
</code></pre>

<a href="http://msdn.microsoft.com/en-us/library/58918ffs%28v=VS.100%29.aspx" rel="noreferrer">typeof (MSDN)</a>

blocks|key|2471970|text|if+(numerator+is+int)+{+...+}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2471971|或|unstyled|2471972|if+(numerator.GetType()+==+typeof(int))+{...}|2471973|前者通常更好。|2471974|编辑:Н我们说问题出在从字符串表示中解析数字。我担心，这里最好的方法是调用type.TryParse并检查给定的字符串是否可以被解析为给定类型的数量。|offset|length|style|CODE|2471975|例如。|2471976|var+tokens+=+line.Split('/');
double+dArg1,dArg2;+int+iArg1,+iArg2;
if+(int.TryParse(tokens[0],+out+iArg1)+
++++&&+int.TryParse(tokens[1],+out+iArg2)){
++++return+iArg1/iArg2;
}+else+if+(double.TryParse(tokens[0],+out+dArg1)+
+++++++++++&&+double.TryParse(tokens[1],+out+dArg2)){
++++return+dArg1/dArg2;
}+else+{+/*+handle+error+*/+}|2471977|请注意，所有的ints都可以解析为doubles，因此您需要先尝试将token解析为int，然后再尝试将其解析为`+`double。|2471978|entityMap^0|0|0|0|0|11|D|0|0|0|7|3|H|6|16|3|0^^$0|@$1|2|3|4|5|6|7|Y|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|10|8|@]|9|@]|A|$B|C]]|$1|I|3|J|5|F|7|11|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|12|8|@$M|13|N|14|O|P]]|9|@]|A|$]]|$1|Q|3|R|5|F|7|15|8|@]|9|@]|A|$]]|$1|S|3|T|5|6|7|16|8|@]|9|@]|A|$B|C]]|$1|U|3|V|5|F|7|17|8|@$M|18|N|19|O|P]|$M|1A|N|1B|O|P]|$M|1C|N|1D|O|P]]|9|@]|A|$]]|$1|W|3|-4|5|F|7|1E|8|@]|9|@]|A|$]]]|X|$]]

<pre><code>if (numerator is int) { ... }
</code></pre>

or 

<pre><code>if (numerator.GetType() == typeof(int)) {...}
</code></pre>

The former is usually better.

EDIT:
Нou say the problem is parsing numbers from string representation. I'm afraid, the best approach here is to call <code>type.TryParse</code> and check if given string can be parsed as a number of given type.

E.g.

<pre><code>var tokens = line.Split('/');
double dArg1,dArg2; int iArg1, iArg2;
if (int.TryParse(tokens[0], out iArg1) 
 &amp;&amp; int.TryParse(tokens[1], out iArg2)){
 return iArg1/iArg2;
} else if (double.TryParse(tokens[0], out dArg1) 
 &amp;&amp; double.TryParse(tokens[1], out dArg2)){
 return dArg1/dArg2;
} else { /* handle error */ }
</code></pre>

Note that all <code>int</code>s can be parsed as <code>double</code>s, so you need to try to parse token as <code>int</code> before trying to parse it as `double.

blocks|key|2757564|text|您应该尝试is/as操作符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2757565|if+(numerator+is+int)+{...}|code-block|syntax|javascript|2757566|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You should try the is/as operator:

<pre><code>if (numerator is int) {...}
</code></pre>

blocks|key|2757579|text|您可以使用typeof-运算符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2757580|if(typeof(int)+==+numerator.GetType())
{
++++//put+code+here
}|code-block|syntax|javascript|2757581|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use the typeof-operator:

<pre><code>if(typeof(int) == numerator.GetType())
{
 //put code here
}
</code></pre>

blocks|key|2757583|text|使用+operator+in+C#。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2757584|if(number+is+int)|code-block|syntax|javascript|2757585|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/scekt9xw%2528v=VS.80%2529.aspx^0|2|F|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Use the <a href="http://msdn.microsoft.com/en-us/library/scekt9xw%28v=VS.80%29.aspx" rel="nofollow">is operator in C#</a>.

<pre><code>if(number is int)
</code></pre>

blocks|key|4547634|text|这应该是可行的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4547635|if+(numerator.GetType()+==+typeof(int))
{
+++//+it's+an+int

}

else+if+(numerator.GetType()+==+typeof(double))
{
+++//+it's+a+double
}|code-block|syntax|javascript|4547636|不知道你为什么要这么做...|4547637|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

This should work:

<pre><code>if (numerator.GetType() == typeof(int))
{
 // it's an int

}

else if (numerator.GetType() == typeof(double))
{
 // it's a double
}
</code></pre>

Not sure why you'd want to do that though...

blocks|key|4547648|text|使用以下内容：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4547649|if+(+value+is+int+)+{+}|code-block|syntax|javascript|4547650|您可能还想看看Generic+Methods+(C#+Programming+Guide)|offset|length|4547651|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/twcad0zb%2528v=VS.100%2529.aspx^0|0|0|7|12|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Use the following:

<pre><code>if ( value is int ) { }
</code></pre>

You may also want to take a look at <a href="http://msdn.microsoft.com/en-us/library/twcad0zb%28v=VS.100%29.aspx" rel="nofollow">Generic Methods (C# Programming Guide)</a>

blocks|key|855145|text|C#+7|type|unstyled|depth|inlineStyleRanges|entityRanges|data|855146|if+(number+is+int+myint)+{//;+do+something+with+myint}+OR

if+(number+is+double+mydouble)+{//;+do+something+with+mydouble}|code-block|syntax|javascript|855147|如果类型匹配，则每种情况都为真。cast值将被放入变量中。|855148|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

C# 7

<pre><code>if (number is int myint) {//; do something with myint} OR

if (number is double mydouble) {//; do something with mydouble}
</code></pre>

Each case is true if the type matches. The cast value will be placed in the variable.

if I have int number in nominator, I will do one method from my1.cs, if I have double number in nominator/denominator I will do method from another class called my2.cs . How I may code IF, 

<code>if (number = int) {//; bla bla bla...}</code> 
OR

<code>if (number = double) {//; bla bla bla...}</code>

How to code this if-statement: <code>if (numerator.GetType==int){...}</code> ?

The main trouble is in this: I read nominator and denominator from textbox, with var dr1 = textBox1.Text.Split('/'); ! split, but how i can gettype from string ???

If-statement GetType() c#

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如果我在nominator中有int number，我将从my1.cs中做一个方法，如果我在nominator/denominator中有两个number，我将从另一个名为my2.cs的类中做方法。我该如何编码如果，if (number = int) {//; bla bla bla...} ORif (number ...

问If语句GetType() c#
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