blocks|key|395805|text|也有一些其他的方法可以做到这一点，但为了简单起见，这应该是可行的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|395806|array+=+[10,+9,+10,+6,+2,+5,+10]
total_count+=+array.size
promoters+=+array.count+{%7Cx%7C+x+>+8}
passives+=+array.count+{%7Cx%7C+x+>+6+&&+x+<9}
detractors+=+array.count+{%7Cx%7C+x+<+7}

promoters_perc+=+promoters.to_f+/+total_count+*+100
detractors_perc+=+detractors.to_f+/+total_count+*+100

score+=+promoters_perc+-+detractors_perc|code-block|syntax|javascript|395807|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

There are a some other ways of doing this as well, but for simplicity this should work.

<pre><code>array = [10, 9, 10, 6, 2, 5, 10]
total_count = array.size
promoters = array.count {|x| x &gt; 8}
passives = array.count {|x| x &gt; 6 &amp;&amp; x &lt;9}
detractors = array.count {|x| x &lt; 7}

promoters_perc = promoters.to_f / total_count * 100
detractors_perc = detractors.to_f / total_count * 100

score = promoters_perc - detractors_perc
</code></pre>

blocks|key|1963824|text|你可以在哈希表中计算你的所有指标：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1963825|arr+=+[10,+9,+10,+6,+2,+5,+10]
count+=+arr.each_with_object(Hash.new(0))+do+%7Ce,+memo%7C
++case+e
++when+0..6+then+memo[:detractors]+%2B=+1
++when+7..8+then+memo[:passives]+%2B=+1
++when+9..10+then+memo[:promoters]+%2B=+1+
++end
end

score+=+(count[:promoters]+-+count[:detractors]).to_f+/+arr.size+*+100
=>+14.285714285714285|code-block|syntax|javascript|1963826|较短的解决方案：|1963827|metrics+=+{+promoters:+9..10,+passives:+7..8,+detractors:+0..6+}
count+=+metrics.each+{%7Ck,+v%7C+metrics[k]+=+arr.count+{%7Ce%7C+v+===+e}}

score+=+(count[:promoters]+-+count[:detractors]).to_f+/+arr.size+*+100
=>+14.285714285714285|1963828|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can count all your metrics in hash:

<pre><code>arr = [10, 9, 10, 6, 2, 5, 10]
count = arr.each_with_object(Hash.new(0)) do |e, memo|
 case e
 when 0..6 then memo[:detractors] += 1
 when 7..8 then memo[:passives] += 1
 when 9..10 then memo[:promoters] += 1 
 end
end

score = (count[:promoters] - count[:detractors]).to_f / arr.size * 100
=&gt; 14.285714285714285
</code></pre>

Shorter solution:

<pre><code>metrics = { promoters: 9..10, passives: 7..8, detractors: 0..6 }
count = metrics.each {|k, v| metrics[k] = arr.count {|e| v === e}}

score = (count[:promoters] - count[:detractors]).to_f / arr.size * 100
=&gt; 14.285714285714285
</code></pre>

blocks|key|395859|text|这是另一种方法，代码是不言自明的。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|395860|data+=+[10,+9,+10,+6,+2,+5,+10]

score_range+=+[promoters+=+(9..10),+passives+=+(7..8),+detractors+=+(0..6)]
#=>+[9..10,+7..8,+0..6]
grouped+=+data.group_by+{%7Ci%7C+score_range.select+{%7Csr%7C+sr.cover?(i)}+}.to_h
#=>+{[9..10]=>[10,+9,+10,+10],+[0..6]=>[6,+2,+5]}
percentage+=+grouped.map+{%7C(k),v%7C+[k,+(v.size++*+100.0/+data.size).round]}.to_h
#=>+{9..10=>57,+0..6=>43}
nps+=+percentage[promoters]+-+percentage[detractors]
#=>+14|code-block|syntax|javascript|395861|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is one more way to do this, code is self explanatory.

<pre><code>data = [10, 9, 10, 6, 2, 5, 10]

score_range = [promoters = (9..10), passives = (7..8), detractors = (0..6)]
#=&gt; [9..10, 7..8, 0..6]
grouped = data.group_by {|i| score_range.select {|sr| sr.cover?(i)} }.to_h
#=&gt; {[9..10]=&gt;[10, 9, 10, 10], [0..6]=&gt;[6, 2, 5]}
percentage = grouped.map {|(k),v| [k, (v.size * 100.0/ data.size).round]}.to_h
#=&gt; {9..10=&gt;57, 0..6=&gt;43}
nps = percentage[promoters] - percentage[detractors]
#=&gt; 14
</code></pre>

The net promoter score can have the values 0-10. It is divided in three groups:

Promoters = respondents giving a 9 or 10 score 
Passives = respondents giving a 7 or 8 score 
Detractors = respondents giving a 0 to 6 score

The score is calculated as the difference between the percentage of Promoters and Detractors.

Let's say we have the scores <code>[10, 9, 10, 6, 2, 5, 10]</code>.

This would give the score +14 (57% - 43%).

I wish I could count occurrences of a range in an array, if that would be possible I would do 

<pre><code>total_count = array.size
promoters = array.count(9..10)
passives = array.count(7..8)
detractors = array.count(0..6)

promoters_perc = promoters.to_f / total_count * 100
detractors_perc = detractors.to_f / total_count * 100

score = promoters_perc - detractors_perc
</code></pre>

How can I do this calculation?

Calculate NPS in Ruby

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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净启动分数的值可以是0-10。它分为三组：推广者=给出9或10分的受访者被动者=给出7或8分的受访者批评者=给出0到6分的受访者得分计算为推动者和批评者的百分比之差。假设我们有分数[10, 9, 10, 6, 2, 5, 10]。这将得到+14 (57% - 43%)的分数。我希望我能计算一个数组中范围的出现次数，如果...

问在Ruby中计算NPS
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