我想使行项目被选中(例如,改变背景或任何指示被选中) ...这是所选两个元素的示例,没有这些元素的影响: 1:https://i.stack.imgur.com/Lb8fh.jpg
下面是我的代码:
@Override
protected void onCreate(Bundle savedInstanceState) {
listApps = (ListView) findViewById(R.id.xmlListView);
listApps.setChoiceMode(ListView.CHOICE_MODE_MULTIPLE_MODAL);
listApps.setMultiChoiceModeListener(new AbsListView.MultiChoiceModeListener() {
@Override
public void onItemCheckedStateChanged(ActionMode actionMode, int i, long l, boolean b) {
actionMode.setTitle(listApps.getCheckedItemCount() + " Selected Items");
//******************************************
// what should i do to reach to row item -_-
//******************************************
}
@Override
public boolean onCreateActionMode(ActionMode actionMode, Menu menu) {
getMenuInflater().inflate(R.menu.menu_item_selected, menu);
return true;
}
@Override
public boolean onPrepareActionMode(ActionMode actionMode, Menu menu) {
return false;
}
@Override
public boolean onActionItemClicked(ActionMode actionMode, MenuItem menuItem) {
return false;
}
@Override
public void onDestroyActionMode(ActionMode actionMode) {
}
});
}
发布于 2020-09-04 02:55:02
您需要创建一个可绘制的选择器,并将其用作ListView
中每个项目布局的背景,以突出显示所选行。
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="@color/highlight_color" android:state_activated="true" />
<item android:drawable="@color/default_color" />
</selector>
https://stackoverflow.com/questions/63727971
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