问mod运算符的困难

EN

int i = 8,  j = 5;
float x = 0.005, y = - 0.01;
char c = 'c',  d = 'd';

(i - 3 * j) % ( c + 2 *d)/ (x - y )

( i- 3 * j) % ( c + 2 *d ) / ( x - y)
( 8 - 3*5) % ( 99 + 2 * 100 ) / ( 0.005 - (-0.01) )
( -7 ) % ( 299 ) / (  0.015 )

( 292 ) / (  0.015 )

#include <stdio.h> 
#include <stdlib.h> 
 
int main() 
{ 
    int i = 8,j = 5, c = 'c',d = 'd'; 
    float x = 0.005, y = -0.01, a = 0.0; // a is the float variable to which the value is assigned
    a = (i-3*j)%(c+2*d)/(x-y); 
    printf("%f\n",a); 
    return 0; 
}