假设我有嵌套的DOM,每个DOM都有对应于不同angular-ui-router
状态的ui-sref
。我想单击以仅警告外部,并单击 inner 以仅警告内部。目前,如果我点击 inner ,它将同时警告外部和内部状态。
HTML:
<!DOCTYPE html>
<html ng-app="plunker">
<head>
<meta charset="utf-8" />
<title>AngularJS Plunker</title>
<script>document.write('<base href="' + document.location + '" />');</script>
<link rel="stylesheet" href="style.css" />
<script data-require="angular.js@1.2.x" src="http://code.angularjs.org/1.2.13/angular.js" data-semver="1.2.13"></script>
<script data-require="ui-router@0.2.8" data-semver="0.2.8" src="http://angular-ui.github.io/ui-router/release/angular-ui-router.js"></script>
<script src="app.js"></script>
</head>
<body ng-controller="MainCtrl">
<a ui-sref="outer" style="width:300px;height:300px;background:yellow;">
Outer
<span ui-sref="inner" style="width:100px;height:100px;background:red;">Inner</span>
</a>
</body>
</html>
Javascript:
var app = angular.module('plunker', ['ui.router']);
'use strict';
app.config(['$stateProvider', '$urlRouterProvider', '$locationProvider', function($stateProvider, $urlRouterProvider, $locationProvider) {
$stateProvider
.state("outer", {
url: "/outer",
resolve: {
test: function() {
alert("Triggered state outer");
return true;
}
}
})
.state("inner", {
url: "/inner",
resolve: {
test: function() {
alert("Triggered state inner");
return true;
}
}
});
}]);
app.controller('MainCtrl', function($scope) {
});
链接:http://plnkr.co/edit/yzgUAA3lLwkF9svzczl3?p=preview
问题
如何防止内部触发外部state?
stopImmediatePropagation
,这样它就不会触发父DOM的DOM了?也许可以手动使用$state.go
?更新1:
由于要求,我无法更改HTML。这只是一个简化的版本,因为在我的代码中,外部元素非常大,包含其他元素。
https://stackoverflow.com/questions/22189985
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