blocks|key|649091|text|您可以对属性使用回调和比较以及数组，您需要将筛选器应用到上面。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|649092|​|649093|var+object+=+{
++++++++"x":+[309339618361.619,+102862032084.12102,+72892839276.09761,+46463392384.54194,+-39360182208.042145],
++++++++"y":+[13950252.45052416,+1158787.402385158,+-4368238.261400843,+1339913.7393283844,+2085336.6277048483],
++++++++"year":+[1991,+1991,+1992,+1992,+1992]
++++},
++++result+=+{};

['x',+'y',+'year'].forEach(function+(p)+{
++++result[p]+=+object[p].filter(function+(a,+i)+{
++++++++return+object.year[i]+===+1991;
++++});
});

console.log(result);|code-block|syntax|javascript|649094|649095|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>You could use a callback with the comparison and an array for the properties, you want apply the filter on.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var object = {
        "x": [309339618361.619, 102862032084.12102, 72892839276.09761, 46463392384.54194, -39360182208.042145],
        "y": [13950252.45052416, 1158787.402385158, -4368238.261400843, 1339913.7393283844, 2085336.6277048483],
        "year": [1991, 1991, 1992, 1992, 1992]
    },
    result = {};

['x', 'y', 'year'].forEach(function (p) {
    result[p] = object[p].filter(function (a, i) {
        return object.year[i] === 1991;
    });
});

console.log(result);</code></pre>
</div>
</div>
</p>


blocks|key|236771|text|您可以使用reduce()并按要筛选的年份索引添加值。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|236772|​|236773|var+obj+=+{
++"x":+[309339618361.619,+102862032084.12102,+72892839276.09761,+46463392384.54194,+-39360182208.042145],
++"y":+[13950252.45052416,+1158787.402385158,+-4368238.261400843,+1339913.7393283844,+2085336.6277048483],
++"year":+[1991,+1991,+1992,+1992,+1992]
}

var+result+=+obj.year.reduce(function(r,+e,+i)+{
++if+(e+==+1991)+{
++++r.x+=+(r.x+%7C%7C+[]).concat(obj.x[i]);
++++r.y+=+(r.y+%7C%7C+[]).concat(obj.y[i]);
++++r.year+=+(r.year+%7C%7C+[]).concat(obj.year[i])
++}
++return+r;
},+{});

console.log(result)|code-block|syntax|javascript|236774|236775|entityMap^0|5|8|0|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|S|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|T|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|U|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|O|$]]

<p>You can use <code>reduce()</code> and add values by index of year that you want to filter by.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var obj = {
  "x": [309339618361.619, 102862032084.12102, 72892839276.09761, 46463392384.54194, -39360182208.042145],
  "y": [13950252.45052416, 1158787.402385158, -4368238.261400843, 1339913.7393283844, 2085336.6277048483],
  "year": [1991, 1991, 1992, 1992, 1992]
}

var result = obj.year.reduce(function(r, e, i) {
  if (e == 1991) {
    r.x = (r.x || []).concat(obj.x[i]);
    r.y = (r.y || []).concat(obj.y[i]);
    r.year = (r.year || []).concat(obj.year[i])
  }
  return r;
}, {});

console.log(result)</code></pre>
</div>
</div>
</p>


blocks|key|236799|text|只需复制obj并迭代year属性的元素并删除不等于1991的元素。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|236800|var+obj+=+{

++++x:++++[309339618361.619,+102862032084.12102],
++++y:++++[13950252.45052416,+1158787.402385158],
++++year:+[1991,+1991]

},

++++scan+=+{};

Object.assign(scan,+obj);

for(var+i+=+0,+len+=+scan.year.length;+i+<+len;+i+%2B%2B)+{

++++if(scan.year[i]+!==+1991)+{

++++++++scan.year.splice(i,+1);

++++}

}

console.log(scan);|code-block|syntax|javascript|236801|entityMap^0|4|3|A|4|P|4|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

<p>Simply do a copy of <code>obj</code> and iterate the elements of the <code>year</code> property and remove which aren't equal to <code>1991</code>.</p>

<pre><code>var obj = {

    x:    [309339618361.619, 102862032084.12102],
    y:    [13950252.45052416, 1158787.402385158],
    year: [1991, 1991]

},

    scan = {};

Object.assign(scan, obj);

for(var i = 0, len = scan.year.length; i &lt; len; i ++) {

    if(scan.year[i] !== 1991) {

        scan.year.splice(i, 1);

    }

}

console.log(scan);
</code></pre>


<p>I have JSON object with array pairs, like this:</p>

<blockquote>
  <p>Object {x: Array[36159], y: Array[36159], year: Array[36159]}</p>
</blockquote>

<p>Small sample as example:</p>

<pre><code>{
    "x": [309339618361.619, 102862032084.12102, 72892839276.09761, 46463392384.54194, -39360182208.042145],
    "y": [13950252.45052416, 1158787.402385158, -4368238.261400843, 1339913.7393283844, 2085336.6277048483],
    "year": [1991, 1991, 1992, 1992, 1992]
}
</code></pre>

<p>I want to filter this object on year. If JSON data was array or key, value pairs, I could have used filter:</p>

<pre><code>data.filter(function (x) {
    return x.year == 1991
});
</code></pre>

<p>but as JSON structure is pairs of flat arrays, I have no idea how to approach.</p>

<hr>

<p>Desired results is this:</p>

<pre><code>{
    "x": [309339618361.619, 102862032084.12102],
    "y": [13950252.45052416, 1158787.402385158],
    "year": [1991, 1991]
}
</code></pre>


Filter JSON object with flat arrays

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有带有数组对的JSON对象，如下所示：对象{x: Array36159，y: Array36159，年份: Array36159}小样本为例：{    "x": [309339618361.619, 102862032084.12102, 72892839276.09761, 46463392384.54194, -...

问用平面数组过滤JSON对象
EN

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问用平面数组过滤JSON对象EN