blocks|key|715139|text|再多一点，你的问题就可以自己解决了:你只需要用正数除以之和：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|715140|def+ave_pos(nums):
++++avg+=+0
++++pos+=+0
++++for+x+in+nums:
++++++++if+x+>+0:
++++++++++++pos+=+pos+%2B+1
++++++++++++avg+=+avg+%2B+x
++++avg+=+avg+/+pos
++++return+avg|code-block|syntax|javascript|715141|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

A little bit more and your problem can be solved by yourself: you just need to divide the sum by the number of the positive elements:

<pre><code>def ave_pos(nums):
 avg = 0
 pos = 0
 for x in nums:
 if x &gt; 0:
 pos = pos + 1
 avg = avg + x
 avg = avg / pos
 return avg
</code></pre>

blocks|key|3464487|text|请使用过滤器和sum：-|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3464488|a+=+[3,+-3,+4,+0,+2,+-1]
apositive+=+filter(lambda+x:x>0,+a)
sum(apositive)/len(apositive)|code-block|syntax|javascript|3464489|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

use filter and sum for this:-

<pre><code>a = [3, -3, 4, 0, 2, -1]
apositive = filter(lambda x:x&gt;0, a)
sum(apositive)/len(apositive)
</code></pre>

blocks|key|1186303|text|计算平均值的公式是total_sum+/+number_of_elements。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1186304|使用计数变量来计数正元素的no并返回sum/count|1186305|count+=0;
sum+=+0+
for+x+in+nums:
+++if+x+>+0:
+++++++sum+=+sum+%2B+x
+++++++count+=+count+%2B+1
return+avg/count|code-block|syntax|javascript|1186306|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

the formula to calculate average is 
total_sum / number_of_elements

Use a count variable to count no of positive element and return sum/count

<pre><code>count =0;
sum = 0 
for x in nums:
 if x &gt; 0:
 sum = sum + x
 count = count + 1
return avg/count
</code></pre>

blocks|key|3464559|text|问题是，你只是把所有的积极因素加起来，而不是计算它们的平均值。变量avg以所有正元素之和结束。要得到平均值，你需要把总数除以有多少。下面是对代码的修改，可以：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3464560|def+ave_pos(nums):
++++total+=+0
++++count+=+0
++++for+x+in+nums:
+++++++if+x+>+0:
+++++++++++total+%2B=+x
+++++++++++count+%2B=+1
++++return+float(total)+/+count|code-block|syntax|javascript|3464561|正如您所看到的，它维护运行的总数和单独计数，并在最后将它们分开。如果您使用的是Python2，那么您需要调用float，否则除法将向下舍入到下一个整数。在Python+3中，这是不必要的。|3464562|entityMap^0|X|3|0|0|1I|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

The problem is that you are just adding up all the positive elements, not computing their average. Your variable <code>avg</code> ends up with the sum of all positive elements. To get the average, you need to divide the sum by how many there were. Here's a modification of your code that works:

<pre><code>def ave_pos(nums):
 total = 0
 count = 0
 for x in nums:
 if x &gt; 0:
 total += x
 count += 1
 return float(total) / count
</code></pre>

As you can see, it maintains the running total and count separately, and divides them out at the end. If you're using Python 2, then you need the call to <code>float</code> otherwise the division will round down to the next integer. In Python 3 this isn't necessary.

blocks|key|715253|text|您可以使用列表理解将所有正数提取到另一个列表中。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|715254|def+mean_positive(L):
++++#+Get+all+positive+numbers+into+another+list
++++pos_only+=+[x+for+x+in+L+if+x+>+0]
++++if+pos_only:
++++++++return+sum(pos_only)+/++len(pos_only)
++++raise+ValueError('No+postive+numbers+in+input')|code-block|syntax|javascript|715255|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use a list comprehension to extract all the positive numbers into another list.

<pre><code>def mean_positive(L):
 # Get all positive numbers into another list
 pos_only = [x for x in L if x &gt; 0]
 if pos_only:
 return sum(pos_only) / len(pos_only)
 raise ValueError('No postive numbers in input')
</code></pre>

Ignore all the negative elements, and only use positive elements to calculate average.

<pre><code>ave_pos([3, -3, 4, 0, 2, -1]) = 3
</code></pre>

Here is what I have so far and I am completely lost on why it's not working!

<pre><code>def ave_pos(nums):
 avg = 0 
 for x in nums:
 if x &gt; 0:
 avg = avg + x
 return avg
</code></pre>

Calculate and return the average of only the positive values in the list

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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忽略所有负元素，只使用正元素计算平均值。ave_pos([3, -3, 4, 0, 2, -1]) = 3这是我到目前为止所拥有的，我完全不明白为什么它不起作用！def ave_pos(nums):    avg = 0     for x in nums:       if x > 0:           avg ...

问只计算并返回列表中正值的平均值。
EN

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问只计算并返回列表中正值的平均值。EN