blocks|key|1274023|text|您可以定义一个比较器来完成此操作。一种简单的方法是使用匿名类。https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1274024|Collections.sort(student,+new+Comparator<Student>()+{
++++public+int+compare(Student+a,+Student+b)+{
++++++++return+a.getName().compare(b.getName());
++++}
};|code-block|syntax|javascript|1274025|entityMap|0|LINK|mutability|MUTABLE|url|https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html^0|V|1V|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You can define a Comparator to do this. One easy way is with an anonymous class.
<a href="https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html" rel="nofollow noreferrer">https://docs.oracle.com/javase/8/docs/api/java/util/Comparator.html</a>

<pre><code>Collections.sort(student, new Comparator&lt;Student&gt;() {
 public int compare(Student a, Student b) {
 return a.getName().compare(b.getName());
 }
};
</code></pre>

blocks|key|27153|text|您可以使用Collections.sort方法接受comparator作为其第二个参数。传入一个定义您想要的排序的comparator。例如，给定一个Student类，您可以使用Collections.sort和自定义comparator对Student进行排序，按如下所示的升序排列：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|27154|import+java.util.Arrays;
import+java.util.Collections;
import+java.util.Comparator;
import+java.util.LinkedList;
import+java.util.List;

class+Student+{

++++private+final+String+name;
++++private+final+int+score;

++++Student(String+name,+int+score)+{
++++++++this.name+=+name;
++++++++this.score+=+score;
++++}

++++public+String+getName()+{
++++++++return+name;
++++}

++++public+int+getScore()+{
++++++++return+score;
++++}

++++@Override
++++public+String+toString()+{
++++++++return+"Student+[name="+%2B+name+%2B+",+score="+%2B+score+%2B+"]";
++++}

++++public+static+void+main(String[]+args)+{
++++++++List<Student>+list+=+new+LinkedList<>(
++++++++++++++++Arrays.asList(new+Student("David",+3),+new+Student("Alice",+3),+new+Student("Thomas",+9)));

++++++++System.out.println("Before+Sort:+"+%2B+list);

++++++++Collections.sort(list,+new+Comparator<Student>()+{
++++++++++++@Override
++++++++++++public+int+compare(Student+o1,+Student+o2)+{
++++++++++++++++return+o1.getName().compareTo(o2.getName());
++++++++++++}
++++++++});

++++++++System.out.println("After+Sort:+"+%2B+list);
++++}

}|code-block|syntax|javascript|27155|这将产生输出。|27156|before:+[Student+[name=David,+score=3],+Student+[name=Alice,+score=3],+Student+[name=Thomas,+score=9]]
after:+[Student+[name=Alice,+score=3],+Student+[name=David,+score=3],+Student+[name=Thomas,+score=9]]|27157|entityMap^0|5|G|P|A|1L|A|23|7|2H|G|31|A|3C|7|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]|$9|11|A|12|B|C]|$9|13|A|14|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|15|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|16|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|17|8|@]|D|@]|E|$I|J]]|$1|O|3|-4|5|6|7|18|8|@]|D|@]|E|$]]]|P|$]]

You can use the <code>Collections.sort</code> method accepts a <code>comparator</code> as its second argument. Pass in a <code>comparator</code> that defines the ordering that you would like. For example given a <code>Student</code> class, you can use <code>Collections.sort</code> with a custom <code>comparator</code> to sort <code>Student</code> by ascending order of name like this:

<pre><code>import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
import java.util.List;

class Student {

 private final String name;
 private final int score;

 Student(String name, int score) {
 this.name = name;
 this.score = score;
 }

 public String getName() {
 return name;
 }

 public int getScore() {
 return score;
 }

 @Override
 public String toString() {
 return "Student [name=" + name + ", score=" + score + "]";
 }

 public static void main(String[] args) {
 List&lt;Student&gt; list = new LinkedList&lt;&gt;(
 Arrays.asList(new Student("David", 3), new Student("Alice", 3), new Student("Thomas", 9)));

 System.out.println("Before Sort: " + list);

 Collections.sort(list, new Comparator&lt;Student&gt;() {
 @Override
 public int compare(Student o1, Student o2) {
 return o1.getName().compareTo(o2.getName());
 }
 });

 System.out.println("After Sort: " + list);
 }

}
</code></pre>

This will produce the output

<pre><code>before: [Student [name=David, score=3], Student [name=Alice, score=3], Student [name=Thomas, score=9]]
after: [Student [name=Alice, score=3], Student [name=David, score=3], Student [name=Thomas, score=9]]
</code></pre>

blocks|key|27159|text|如果您使用java+>+8，您可以使用Lambda表达式，得到如下内容：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|27160|Collections.sort(student,+(p1,+p2)+->+p1.name.compareTo(p2.name));|CODE|27161|或者在列表中使用排序方法|27162|student.sort((p1,+p2)+->+p1.name.compareTo(p2.name));|27163|entityMap^0|J|9|0|0|1U|0|0|0|1H|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@$9|S|A|T|B|H]]|D|@]|E|$]]|$1|I|3|J|5|6|7|U|8|@]|D|@]|E|$]]|$1|K|3|L|5|6|7|V|8|@$9|W|A|X|B|H]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|N|$]]

if you use java > 8. You can use Lambda expression, and you get something like this:

<code>Collections.sort(student, (p1, p2) -&gt; p1.name.compareTo(p2.name));</code>

or Using sort method in List

<code>student.sort((p1, p2) -&gt; p1.name.compareTo(p2.name));</code>

blocks|key|27165|text|student.sort(Comparator.comparing(Student::getName));|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|27166|阅读更多关于比较器的信息。|unstyled|offset|length|27167|entityMap|0|LINK|mutability|MUTABLE|url|https://www.mkyong.com/java8/java-8-lambda-comparator-example/^0|0|6|3|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@]|9|@$G|S|H|T|1|U]]|A|$]]|$1|I|3|-4|5|F|7|V|8|@]|9|@]|A|$]]]|J|$K|$5|L|M|N|A|$O|P]]]]

<pre><code>student.sort(Comparator.comparing(Student::getName));
</code></pre>

Read more about <a href="https://www.mkyong.com/java8/java-8-lambda-comparator-example/" rel="nofollow noreferrer">comparators</a>.

blocks|key|1274050|text|简单地说你可以用这个|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1274051|+++student.sort(Comparator.comparing(Student::+getName));//Single+Sorting
++++student.sort(Comparator.comparing(Student::+getName).reversed());//Single+reverse+Sorting
++++student.sort(Comparator.comparing(Student::+getName).thenComparing(Student::getScore));//Double|code-block|syntax|javascript|1274052|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

simply you can use this

<pre><code> student.sort(Comparator.comparing(Student:: getName));//Single Sorting
 student.sort(Comparator.comparing(Student:: getName).reversed());//Single reverse Sorting
 student.sort(Comparator.comparing(Student:: getName).thenComparing(Student::getScore));//Double
</code></pre>

I have a List:

<pre><code> LinkedList&lt;Student&gt; student = new LinkedList&lt;Student&gt;();
</code></pre>

In the Student class, it has an attribute String name. I want to sort the List students by its name.
Is there any way I could do that?

Sort LinkedList in Java

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我有一份清单： LinkedList<Student> student = new LinkedList<Student>();在Student类中，它有一个属性字符串名。我想按学生的名字对名单进行排序。有什么办法我能做到吗？

问用Java对LinkedList进行排序
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问用Java对LinkedList进行排序EN