我可以使用以下代码成功发布一条消息:
using (IAdvancedBus bus = RabbitHutch.CreateBus("host=192.168.153.128:5672;username=user;password=pass").Advanced)
{
IExchange exchange = bus.ExchangeDeclare("milk.api", ExchangeType.Topic);
IQueue queue = bus.QueueDeclare("milkorderqueue");
IBinding binding = bus.Bind(exchange, queue, "#");
bus.Publish<MilkOrderRequest>(exchange, "#", true, new Message<MilkOrderRequest>(milkOrder));
}
return new HttpResponseMessage(System.Net.HttpStatusCode.OK);
当我的订阅者试图获取消息时,EasyNetQ_Default_Error_Queue队列就会递增。以下是监听程序的代码:
IBus bus = RabbitHutch.CreateBus(@"host=192.168.153.128:5672;username=user;password=pass");
bus.Subscribe<MilkOrderRequest>("my_subscription_id", message =>
{
Console.WriteLine($"Order recieved: {message.Milk}.");
}, config =>
{
config.WithQueueName("milkorderqueue");
});
我还尝试了以下几种方法,但都没有成功:
IAdvancedBus bus = RabbitHutch.CreateBus(@"host=192.168.153.128:5672;username=user;password=pass").Advanced;
IExchange exchange = bus.ExchangeDeclare("milkshop.subscriber", ExchangeType.Topic);
IQueue queue = bus.QueueDeclare("milkorderqueue");
bus.Bind(exchange, queue, "#");
bus.Consume<MilkOrderRequest>(queue, (message, info) =>
{
Console.WriteLine($"Order recieved: {message.Body.Milk}.");
});
我在谷歌上找不到关于这个例外的答案:
messageType不能为空
下面是完整的信息:
{
"RoutingKey":"#",
"Exchange":"milk.api",
"Queue":"milkorderqueue",
"Exception":"System.AggregateException: One or more errors occurred. (messageType must not be null\r\nParameter name: messageType) ---> System.ArgumentNullException: messageType must not be null\r\nParameter name: messageType\r\n at EasyNetQ.Preconditions.CheckNotNull[T](T value, String name, String message)\r\n at EasyNetQ.Preconditions.CheckNotNull[T](T value, String name)\r\n at EasyNetQ.MessageFactory.CreateInstance(Type messageType, Object body, MessageProperties properties)\r\n at EasyNetQ.RabbitAdvancedBus.<>c__DisplayClass17_0.<Consume>b__0(Byte[] body, MessageProperties properties, MessageReceivedInfo messageReceivedInfo)\r\n at EasyNetQ.Consumer.HandlerRunner.InvokeUserMessageHandler(ConsumerExecutionContext context)\r\n --- End of inner exception stack trace ---\r\n---> (Inner Exception #0) System.ArgumentNullException: messageType must not be null\r\nParameter name: messageType\r\n at EasyNetQ.Preconditions.CheckNotNull[T](T value, String name, String message)\r\n at EasyNetQ.Preconditions.CheckNotNull[T](T value, String name)\r\n at EasyNetQ.MessageFactory.CreateInstance(Type messageType, Object body, MessageProperties properties)\r\n at EasyNetQ.RabbitAdvancedBus.<>c__DisplayClass17_0.<Consume>b__0(Byte[] body, MessageProperties properties, MessageReceivedInfo messageReceivedInfo)\r\n at EasyNetQ.Consumer.HandlerRunner.InvokeUserMessageHandler(ConsumerExecutionContext context)<---\r\n",
"Message":"{\"Milk\":\"semi-skimmed\"}",
"DateTime":"2018-06-01T11:01:11.645241Z",
"BasicProperties":{
"ContentType":null,
"ContentEncoding":null,
"Headers":{
},
"DeliveryMode":0,
"Priority":0,
"CorrelationId":"fe1561c1-4c7c-4489-857e-b664f27a5e5f",
"ReplyTo":null,
"Expiration":null,
"MessageId":null,
"Timestamp":0,
"Type":"Milkshop.Common.MilkOrderRequest:Milkshop.Common",
"UserId":null,
"AppId":null,
"ClusterId":null,
"ContentTypePresent":false,
"ContentEncodingPresent":false,
"HeadersPresent":true,
"DeliveryModePresent":false,
"PriorityPresent":false,
"CorrelationIdPresent":true,
"ReplyToPresent":false,
"ExpirationPresent":false,
"MessageIdPresent":false,
"TimestampPresent":false,
"TypePresent":true,
"UserIdPresent":false,
"AppIdPresent":false,
"ClusterIdPresent":false
}
}
我在.Net核心应用程序上使用EasynetQ版本3.0.0
发布于 2018-06-02 02:59:22
已找到错误。我的应用程序接口项目和控制台应用程序使用不同版本的EasynetQ nuget包。一个是2.33,另一个是3.0.0。
发布于 2018-09-15 00:20:45
我不知道你是否仍然面临这个问题,我发现我自己至少挣扎了3天,这似乎是Netcore2的DefaultMessageSerializationStrategy,的问题。我能够使用我在互联网上找到的这些自定义类来修复:
最后,您可以创建自己的DefaultMessageSerializationStrategy实例并使用DI:
r.Register<IMessageSerializationStrategy>(new DefaultMessageSerializationStrategy(new TypeNameSerializer(), new MyJsonSerializer(new TypeNameSerializer()), new DefaultCorrelationIdGenerationStrategy()));
不是最好的解决方案,但确实做到了:D PD:我没有指向上面实现的链接,但你肯定可以在互联网上搜索到它们。
发布于 2020-04-16 07:17:57
我也有同样的问题,但在我的例子中,我试图在RabbitMQ管理控制台上发布一条消息,并在我的应用程序上消费。它不起作用。
尝试用相同的EasyNetQ版本做另一个应用程序(我做了另一个方法来模拟在同一个应用程序上的发布),并使用publish方法。
https://stackoverflow.com/questions/50648956
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