我绑定了两个标签,通过一系列对Bindings.when()的嵌套调用来计算第二个标签的值。既然我对3个相似的标签连续做了3次完全相同的事情,有没有办法通过重载其中一个绑定方法或IntegerBinding方法来简化这段代码?
private IntegerProperty ipStrength, ipAgility, ipIntelligence;
private IntegerProperty ipStBonus, ipAgBonus, ipInBonus;
public RolePlayingCharacter() {
...
ipStBonus.bind(Bindings.when(ipStrength.lessThan(5))
.then(-1)
.otherwise(Bindings.when(ipStrength.lessThan(9))
.then(0)
.otherwise(Bindings.when(ipStrength.lessThan(11))
.then(1)
.otherwise(2))));
ipAgBonus.bind(Bindings.when(ipAgility.lessThan(5))
.then(-1)
.otherwise(Bindings.when(ipAgility.lessThan(9))
.then(0)
.otherwise(Bindings.when(ipAgility.lessThan(11))
.then(1)
.otherwise(2))));
ipInBonus.bind(Bindings.when(ipIntelligence.lessThan(5))
.then(-1)
.otherwise(Bindings.when(ipIntelligence.lessThan(9))
.then(0)
.otherwise(Bindings.when(ipIntelligence.lessThan(11))
.then(1)
.otherwise(2))));
...
我发现我可以重写Class IntegerBinding的computeValue方法,但这似乎没有任何帮助,因为我无论如何都要做3次,每个标签一次:
IntegerBinding ibStatBonus = new IntegerBinding() {
{
super.bind(ipStrength);
}
@Override
protected int computeValue() {
int iStatValue = ipStrength.get();
if (iStatValue < 5) {
return -1;
} else if (iStatValue < 9) {
return 0;
} else if (iStatValue < 11) {
return 1;
} else {
return 2;
}
}
};
我希望能够做一些简单的事情,比如:
ipStBonus.bind(ipStrength.calculateStatBonus());
ipAgBonus.bind(ipAgility.calculateStatBonus());
ipInBonus.bind(ipIntelligence.calculateStatBonus());
我如何实现这样的东西呢?如何使caclulateStatBonus方法成为IntegerProperty可用的方法列表的一部分?
发布于 2018-08-10 08:53:46
总是可以为此创建一个助手方法:
public static IntegerBinding createStatBonusBinding(final IntegerProperty source) {
return Bindings.createIntegerBinding(() -> {
int value = source.get();
if (value < 5) {
return -1;
}
if (value < 9) {
return 0;
}
if (value < 11) {
return 1;
}
return 2;
}, source);
}
ipStBonus.bind(createStatBonusBinding(ipStrength));
ipAgBonus.bind(createStatBonusBinding(ipAgility));
ipInBonus.bind(createStatBonusBinding(ipIntelligence));
https://stackoverflow.com/questions/51777345
复制相似问题