我有一个非常简单的登录系统,它在一个有3列的MySql数据库上工作:-Username -Password -LinkToSite
如果登录成功,点击Submit按钮后,相关的LinkToSite (超链接)应该会在浏览器中打开。我如何才能做到这一点?
<?php
$uname=$_POST['uname'];//username
$password=$_POST['password'];//password
session_start();
$con=mysqli_connect("localhost","root","","login");//mysqli("localhost","username of database","password of database","database name")
$result=mysqli_query($con,"SELECT * FROM `login_info` WHERE `uname`='$uname' && `password`='$password'");
$count=mysqli_num_rows($result);
if($count==1)
{
echo "Login success";
$_SESSION['log']=1;
}
else
{
echo "please fill proper details";
header("refresh:2;url=index.php");// it takes 2 sec to go index page
}
?>
https://stackoverflow.com/questions/51072296
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