我们的团队正在开发一个用PHP远程访问3D打印机的web应用程序。我们尝试使用多部分/表单数据实现POST print_job部件,但它不起作用,显示未收到任何文件。此API将检查id和密钥。下面是代码。如有任何帮助,我们不胜感激!
它运行在Apache 2.4.39,PHP 7.3.5,XAMPP控制面板3.2.2上。
详细信息如下:
<?php
function callAPI($method, $url, $data){
$curl = curl_init();
switch ($method){
case "POST":
curl_setopt($curl, CURLOPT_HEADER, 0);
curl_setopt($curl, CURLOPT_POST, 1);
if ($data)
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
break;
case "PUT":
curl_setopt($curl, CURLOPT_HEADER, true);
curl_setopt($curl, CURLOPT_CUSTOMREQUEST, "PUT");
if ($data)
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
break;
default:
if ($data)
$url = sprintf("%s?%s", $url, http_build_query($data));
}
$username = "";
$password = "";
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_HTTPAUTH, CURLAUTH_DIGEST);
curl_setopt($curl, CURLOPT_USERPWD, $username . ":" . $password);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($curl, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($curl, CURLOPT_TIMEOUT, 90);
curl_setopt($curl, CURLINFO_HEADER_OUT, true);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
// EXECUTE:
$result = curl_exec($curl);
if(!$result){die("Connection Failure");}
curl_close($curl);
return $result;
}
?>
<?php
include('api.php');
$_SESSION['ip'] = "";
$_SESSION['url'] = "http://".$_SESSION['ip']."/api/v1";
$target_dir = "../uploads/";
$target_file = $target_dir . basename($_FILES["file"]["name"]);
move_uploaded_file($_FILES["file"]["tmp_name"], $target_file);
$filedata = $_FILES["file"]["tmp_name"];
echo $target_file;
$data_array = array(
"jobname" => "file",
"file" => "new \CURLFile(realpath($filedata))"
);
$_SESSION['size'] = $_FILES['file']['size'];
//$make_call = callAPI('POST', $_SESSION['url']."/print_job", $data_array);
$response = callAPI('POST', $_SESSION['url']."/print_job", $data_array);
$_SESSION['print'] = $response;
header('location: ../index.php');
?>
Ps:如果我想上传从前端获得的文件到远程API,我可能必须将其存储在本地。然后我像下面的代码一样试了试。它起作用了。
file_put_contents("E:/xyz/test.gcode",file_get_contents("../uploads/".$_FILES["file"]["name"]));
$filedata='E:/xyz/test.gcode';
if(!is_readable(realpath($filedata))){throw new \RuntimeException("upload file not readable!");}
$data_array = array(
'jobname' => 'file',
'file' => new \CURLFile($filedata)
);
发布于 2019-05-19 22:26:24
首先,不要手动设置Content-Type:multipart/form-data
头,因为这样做会破坏边界。完整的标题看起来像这样:
Content-Type: multipart/form-data; boundary=------------------------777d48028c332f50
所以把这个去掉:
$headers = array("Content-Type:multipart/form-data");
让curl为你设置。(当将CURLOPT_POSTFIELDS设置为数组时,curl将使用正确的边界自动设置该标头。)
其次,您在这里发送的并不是实际的文件,而只是发送文字字符串
new \CURLFile(realpath($filedata))
。。如果要发送$filedata指向的文件,请执行以下操作
$data_array = array(
"jobname" => "test",
"file" => new \CURLFile(realpath($filedata))
);
而不是。
https://stackoverflow.com/questions/56204248
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