有没有一种在Java中打印异常消息而不显示异常的方法?
当我尝试以下代码时:
try {
// statements
} catch (javax.script.ScriptException ex) {
System.out.println(ex.getMessage());
}
输出为:
Invalid JavaScript code: sun.org.mozilla.javascript.internal.EvaluatorException:
missing } after property list (<Unknown source>) in <Unknown source>;
at line number 1
有没有办法打印没有异常信息、来源和行号信息的消息?换句话说,我想在输出中打印的消息是:
missing } after property list
https://stackoverflow.com/questions/15722763
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