我不能执行动态日志记录fileHandle更改。
例如,我有3个班级
one.py
import logging
class One():
def __init__(self,txt="?"):
logging.debug("Hey, I'm the class One and I say: %s" % txt)
two.py
import logging
class Two():
def __init__(self,txt="?"):
logging.debug("Hey, I'm the class Two and I say: %s" % txt)
config.py
import logging
class Config():
def __init__(self,logfile=None):
logging.debug("Reading config")
self.logfile(logfile)
myapp
from one import One
from two import Two
from config import Config
import logging
#Set default logging
logging.basicConfig(
level=logging.getLevelName(DEBUG),
format='%(asctime)s - %(name)s - %(levelname)s - %(message)s',
filename=None
)
logging.info("Starting with stdout")
o=One(txt="STDOUT")
c=Config(logfile="/tmp/logfile")
# Here must be the code that change the logging configuration and set the filehandler
t=One(txt="This must be on the file, not STDOUT")
如果我再次尝试loggin.basicConfig()
,它不起作用。
发布于 2017-11-23 12:13:30
@Martijn提供的答案运行良好。但是,代码截取程序会移除所有处理程序,只放回文件处理程序。如果您的应用程序有由其他模块添加的处理程序,这将会很麻烦。
因此,下面的代码片段被设计成只替换文件处理程序。
if isinstance(hdlr,logging.FileHandler)
这一行是关键。
import logging
filehandler = logging.FileHandler('/tmp/logfile', 'a')
formatter = logging.Formatter('%(asctime)-15s::%(levelname)s::%(filename)s::%(funcName)s::%(lineno)d::%(message)s')
filehandler.setFormatter(formatter)
log = logging.getLogger() # root logger - Good to get it only once.
for hdlr in log.handlers[:]: # remove the existing file handlers
if isinstance(hdlr,logging.FileHandler):
log.removeHandler(hdlr)
log.addHandler(filehandler) # set the new handler
# set the log level to INFO, DEBUG as the default is ERROR
log.setLevel(logging.DEBUG)
发布于 2016-02-01 05:59:54
我找到了一种比上面的“接受”答案更简单的方法。如果有对处理程序的引用,则只需调用close()方法,然后设置baseFilename属性。在分配baseFilename时,请确保使用os.path.abspath()。在库源代码中有一个注释,表明它是必需的。我将我的配置内容保存在全局dict()中,这样很容易保存FileHandler引用对象。如下所示,只需要两行代码就可以动态更改处理程序的日志文件名。
import logging
def setup_logging():
global config
if config['LOGGING_SET']:
config['LOG_FILE_HDL'].close()
config['LOG_FILE_HDL'].baseFilename = os.path.abspath(config['LOG_FILE'])
config['DEBUG_LOG_HDL'].close()
config['DEBUG_LOG_HDL'].baseFilename = os.path.abspath(config['DEBUG_LOG'])
else:
format_str = '%(asctime)s - %(name)s - %(levelname)s - %(message)s'
formatter = logging.Formatter(format_str)
log = logging.getLogger()
log.setLevel(logging.DEBUG)
# add file mode="w" to overwrite
config['LOG_FILE_HDL'] = logging.FileHandler(config['LOG_FILE'], mode='a')
config['LOG_FILE_HDL'].setLevel(logging.INFO)
config['LOG_FILE_HDL'].setFormatter(formatter)
log.addHandler(config['LOG_FILE_HDL'])
# the delay=1 should prevent the file from being opened until used.
config['DEBUG_LOG_HDL'] = logging.FileHandler(config['DEBUG_LOG'], mode='a', delay=1)
config['DEBUG_LOG_HDL'].setLevel(logging.DEBUG)
config['DEBUG_LOG_HDL'].setFormatter(formatter)
log.addHandler(config['DEBUG_LOG_HDL'])
ch = logging.StreamHandler()
ch.setLevel(logging.DEBUG)
ch.setFormatter(formatter)
log.addHandler(ch)
config['LOGGING_SET'] = True
发布于 2019-01-24 06:08:43
我试着结合@Arun Thundyill Saseendran来实现@Martijn在这个页面上的建议。我太新了,不允许发表评论,所以我必须发布一个调整后的答案。在isinstance调用中,我必须使用'logging‘而不是'log’来访问类型(log是一个实例),然后'FileHander‘应该是'FileHandler’。我使用的是Python 3.6。
import logging
filehandler = logging.FileHandler('/tmp/logfile', 'a')
formatter = logging.Formatter('%(asctime)-15s::%(levelname)s::%(filename)s::%(funcName)s::%(lineno)d::%(message)s')
filehandler.setFormatter(formatter)
log = logging.getLogger() # root logger - Good to get it only once.
for hdlr in log.handlers[:]: # remove the existing file handlers
if isinstance(hdlr,logging.FileHandler): #fixed two typos here
log.removeHandler(hdlr)
log.addHandler(filehandler) # set the new handler
# set the log level to INFO, DEBUG as the default is ERROR
logging.setLevel(log.DEBUG)
https://stackoverflow.com/questions/13839554
复制相似问题