下面是我读取excel文件的代码。
代码。
FileInfo newFile = new FileInfo("C:\\Excel\\SampleStockTakeExceptionReport.xls");
ExcelPackage pck = new ExcelPackage(newFile);
var ws = pck.Workbook.Worksheets.Add("Content");
ws.View.ShowGridLines = false;
ws.Cells["J12"].Value = "Test Write";
pck.Save();
System.Diagnostics.Process.Start("C:\\Excel\\SampleStockTakeExceptionReport.xls");
当我运行代码时,它抛出了一个运行时错误。
错误
System.Exception: Can not open the package. Package is an OLE compound document. If this is an encrypted package, please supply the password ---> System.IO.FileFormatException: File contains corrupted data.
at MS.Internal.IO.Zip.ZipIOEndOfCentralDirectoryBlock.FindPosition(Stream archiveStream)
at MS.Internal.IO.Zip.ZipIOEndOfCentralDirectoryBlock.SeekableLoad(ZipIOBlockManager blockManager)
at MS.Internal.IO.Zip.ZipArchive..ctor(Stream archiveStream, FileMode mode, FileAccess access, Boolean streaming, Boolean ownStream)
at MS.Internal.IO.Zip.ZipArchive.OpenOnStream(Stream stream, FileMode mode, FileAccess access, Boolean streaming)
at System.IO.Packaging.ZipPackage..ctor(Stream s, FileMode mode, FileAccess access, Boolean streaming)
at System.IO.Packaging.Package.Open(Stream stream, FileMode packageMode, FileAccess packageAccess, Boolean streaming)
at System.IO.Packaging.Package.Open(Stream stream, FileMode packageMode, FileAccess packageAccess)
at OfficeOpenXml.ExcelPackage.ConstructNewFile(Stream stream, String password)
--- End of inner exception stack trace ---
at OfficeOpenXml.ExcelPackage.ConstructNewFile(Stream stream, String password)
at OfficeOpenXml.ExcelPackage..ctor(FileInfo newFile)
at Report.Form1.ExportToExcel1(DataTable Tbl, String ExcelFilePath) in C:\SMARTAG_PROJECT\SUREREACH\EXCEL\Report\Report\Form1.cs:line 39
如果有人能在这方面提供建议/帮助,我将不胜感激。谢谢。
https://stackoverflow.com/questions/14134712
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