假设我们有一个ARGB颜色:
Color argb = Color.FromARGB(127, 69, 12, 255); //Light Urple.
当在现有颜色上绘制此颜色时,颜色将混合。因此,当它与白色混合时,得到的颜色是Color.FromARGB(255, 162, 133, 255);
解决方案应该是这样工作的:
Color blend = Color.White;
Color argb = Color.FromARGB(127, 69, 12, 255); //Light Urple.
Color rgb = ToRGB(argb, blend); //Same as Color.FromARGB(255, 162, 133, 255);
ToRGB
的实现是什么?
发布于 2013-06-26 18:52:29
我知道这是一个旧的线程,但我想添加以下内容:
Public Shared Function AlphaBlend(ByVal ForeGround As Color, ByVal BackGround As Color) As Color
If ForeGround.A = 0 Then Return BackGround
If BackGround.A = 0 Then Return ForeGround
If ForeGround.A = 255 Then Return ForeGround
Dim Alpha As Integer = CInt(ForeGround.A) + 1
Dim B As Integer = Alpha * ForeGround.B + (255 - Alpha) * BackGround.B >> 8
Dim G As Integer = Alpha * ForeGround.G + (255 - Alpha) * BackGround.G >> 8
Dim R As Integer = Alpha * ForeGround.R + (255 - Alpha) * BackGround.R >> 8
Dim A As Integer = ForeGround.A
If BackGround.A = 255 Then A = 255
If A > 255 Then A = 255
If R > 255 Then R = 255
If G > 255 Then G = 255
If B > 255 Then B = 255
Return Color.FromArgb(Math.Abs(A), Math.Abs(R), Math.Abs(G), Math.Abs(B))
End Function
public static Color AlphaBlend(Color ForeGround, Color BackGround)
{
if (ForeGround.A == 0)
return BackGround;
if (BackGround.A == 0)
return ForeGround;
if (ForeGround.A == 255)
return ForeGround;
int Alpha = Convert.ToInt32(ForeGround.A) + 1;
int B = Alpha * ForeGround.B + (255 - Alpha) * BackGround.B >> 8;
int G = Alpha * ForeGround.G + (255 - Alpha) * BackGround.G >> 8;
int R = Alpha * ForeGround.R + (255 - Alpha) * BackGround.R >> 8;
int A = ForeGround.A;
if (BackGround.A == 255)
A = 255;
if (A > 255)
A = 255;
if (R > 255)
R = 255;
if (G > 255)
G = 255;
if (B > 255)
B = 255;
return Color.FromArgb(Math.Abs(A), Math.Abs(R), Math.Abs(G), Math.Abs(B));
}
发布于 2008-08-06 06:39:12
如果你不需要知道这个预渲染,我相信你可以使用getpixel的win32方法。
注意:在密苏里州中部的iPhone上打字,不能上网。我将查找真实的win32示例,并查看是否存在与.net等效的示例。
如果有人关心,并且不想使用上面发布的(很好的)答案,您可以通过此链接MSDN example获取.Net中像素的颜色值
https://stackoverflow.com/questions/2780
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