在pyqt5 /Python3中，当主GUI窗口关闭时，如何使子线程关闭？
在pyqt5 /Python3中，当主GUI窗口关闭时，如何使子线程关闭？
提问于 2020-04-11 10:18:35
我正在使用pyqt5 (Python3.6)编写图形用户界面。我正在尝试运行与主GUI并行的另一个线程。我希望这个子线程在我关闭主应用程序时终止。在本例中，子线程是一个简单的计数器。当我关闭主GUI时，计数器仍然在运行。如何让线程在GUI窗口关闭时结束？在实际情况中，我可能有一个线程正在运行需要几分钟才能执行的操作。我不愿意在线程中使用标志来评估它是否应该结束，因为在GUI窗口关闭后，线程可能需要几分钟才能关闭。我更希望线程立即结束。有什么建议吗？谢谢。
from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton,
QVBoxLayout)
import time, threading, sys
class testScriptApp(QtWidgets.QWidget):
def __init__(self, parent=None):
# initialize th widget
QtWidgets.QWidget.__init__(self, parent)
# set the window title
self.setWindowTitle("Scripting")
# manage the layout
self.mainGrid = QVBoxLayout()
self.button = QPushButton('Start')
self.button.clicked.connect(self.on_click)
self.mainGrid.addWidget(self.button)
self.setLayout(self.mainGrid)
def on_click(self):
self.worker = threading.Thread(target=Worker)
self.worker.daemon = True
self.worker.start()
def Worker(count=1):
while count>0:
print(count)
time.sleep(2)
count+=1
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
myapp = testScriptApp()
myapp.show()
app.exec_()回答 2
Stack Overflow用户
发布于 2020-04-11 11:04:47
我试图使用QThread，但这锁定了主图形用户界面。我不确定我是否正确地实现了它。
from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton,
QVBoxLayout)
from PyQt5.QtCore import QThread
import time, threading, sys
class testScriptApp(QtWidgets.QWidget):
def __init__(self, parent=None):
# initialize th widget
QtWidgets.QWidget.__init__(self, parent)
# set the window title
self.setWindowTitle("Scripting")
# manage the layout
self.mainGrid = QVBoxLayout()
self.button = QPushButton('Start')
self.button.clicked.connect(self.on_click)
self.mainGrid.addWidget(self.button)
self.setLayout(self.mainGrid)
def on_click(self):
self.worker = Worker()
self.worker.run()
def closeEvent(self,event):
print('Closing')
self.worker.terminate()
event.accept()
class Worker(QThread):
def __init__(self):
QThread.__init__(self)
def run(self):
count=1
while count>0:
print(count)
time.sleep(2)
count+=1
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
myapp = testScriptApp()
myapp.show()
app.exec_()Stack Overflow用户
发布于 2020-12-01 23:42:57
from PyQt5 import QtWidgets
from PyQt5.QtWidgets import (QWidget, QApplication,QPushButton,
QVBoxLayout)
from PyQt5.QtCore import QThread,QObject
import time, threading, sys
class testScriptApp(QtWidgets.QWidget):
def __init__(self, parent=None):
# initialize th widget
QtWidgets.QWidget.__init__(self, parent)
# set the window title
self.setWindowTitle("Scripting")
# manage the layout
self.mainGrid = QVBoxLayout()
self.button = QPushButton('Start')
self.button.clicked.connect(self.on_click)
self.mainGrid.addWidget(self.button)
self.setLayout(self.mainGrid)
def on_click(self):
self.my_thread = QThread()
self.worker = Worker()
self.worker.moveToThread(self.my_thread)
self.my_thread.started.connect(self.worker.run)
self.my_thread.start()
def closeEvent(self,event):
print('Closing')
class Worker(QObject):
def __init__(self):
super().__init__()
def run(self):
count=1
while count>0:
print(count)
time.sleep(2)
count+=1
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
myapp = testScriptApp()
myapp.show()
app.exec_()页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/61151313
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