我有这个散列:
h
=> {"67676.mpa"=>{:link=>"pool/sdafdsaff", :size=>4556}}
> h.each do |key, value|
> puts key
> puts value
> end
67676.mpa
linkpool/sdafdsaffsize4556
如何访问循环上的值哈希中的单独的值?
发布于 2012-02-14 23:49:13
Value是一个Hash to,所以你需要对它进行迭代,或者你只能获得值:-
h.each do |key, value|
puts key
value.each do |k,v|
puts k
puts v
end
end
或
h.each do |key, value|
puts key
value.values.each do |v|
puts v
end
end
发布于 2013-04-13 00:49:48
你会想要递归遍历散列,下面是一个递归方法:
def ihash(h)
h.each_pair do |k,v|
if v.is_a?(Hash)
puts "key: #{k} recursing..."
ihash(v)
else
# MODIFY HERE! Look for what you want to find in the hash here
puts "key: #{k} value: #{v}"
end
end
end
然后,您可以获取任何散列并将其传递给:
h = {
"x" => "a",
"y" => {
"y1" => {
"y2" => "final"
},
"yy1" => "hello"
}
}
ihash(h)
发布于 2014-07-02 12:06:43
我稍微改进了Travis的回答,这个要点怎么样:
https://gist.github.com/kjakub/be17d9439359d14e6f86
class Hash
def nested_each_pair
self.each_pair do |k,v|
if v.is_a?(Hash)
v.nested_each_pair {|k,v| yield k,v}
else
yield(k,v)
end
end
end
end
{"root"=>{:a=>"tom", :b=>{:c => 1, :x => 2}}}.nested_each_pair{|k,v|
puts k
puts v
}
https://stackoverflow.com/questions/9279768
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