如果"statement if“为真，如何停止算法？
如果"statement if“为真，如何停止算法？
提问于 2021-08-04 04:28:01
我有一个if/else语句，像这样：
import numpy as np
rows_b = int(input("Enter the number of rows of matrix B : " ))
column_b = int(input("Enter the number of columns of matrix B : "))
print("Input elements of matrix B1:")
B1= [[float(input()) for i in range(column_b)] for j in range(rows_b)]
print("Input elements of matrix B2:")
B2= [[float(input()) for i in range(column_b)] for j in range(rows_b)]
b1 = np.array(B1)
b2 = np.array(B2)
result = np.all(b1 == b2[0])
if result:
print('matrix B1 = B2')
#if matrix B1 = B2, go to the next algorithm
else:
print('matrix B1 and B2 are not equivalent')
#if B1 and B2 are not equivalent, stop here.
B = np.array(B1)
print("Matrix B is: ")
for x in B:
print(x)我想如果B1 = B2，那么继续下一步(B = np.array ( B1 ))但是(else)如果B1和B2不相等，那么停止算法(不继续到B= np.array (B1))，如何？
回答 1
Stack Overflow用户
回答已采纳
发布于 2021-08-04 04:31:03
将其放入if中
if B1 == B2:
B = np.array(B1)
print("Matrix B is: ")
for x in B:
print(x)
else:
print('matrix B1 and B2 are not equivalent')
#if B1 and B2 are not equivalent, stop here.页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/68651264
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