static public int FindMaxIndex<T>( IEnumerable<IComparable<T>> arr ) IEnumerator<IComparable<Double>> arr = new List<IComparable<Double>>(); // THIS WORKS
List<Double> ar
我正在尝试使用VB.NET创建一个快速排序基类,将其作为IComparable元素的数组。Dim numbers(100) as doublefor i as integer = 0 to numbers.length - 1Error 88 Value of type '1-dimensional array of Double' cannot be converted to '1-dimensionalarray
我有一个数据系列List<Tuple<string,double>>,我用它创建一个XyDataSeries<double, double>。我使用以下LabelFormatter。} { public ITickLabelViewModel CreateDataContext(IComparabledataValue) var index = (doubl
但问题是RegressionMetrics接受RDD[(Double, Double)],而output的格式是DStream[Double,Double]。如何将output转换为RDD[(Double, Double)]以便能够使用RegressionMetrics
val model = new StreamingLinearRegressionWithSGD
错误1 'Koordinates.Vieta‘不能实现接口成员’System.IComparable.CompareTo(对象)‘
public class Vieta : IComparable//error is thrown here, on "Vieta" public double x, y; public Vieta(doublea, double</em