交换具有相同类名的多个文件路径

import os

def swap_file_paths(file_paths):
    # 获取文件路径中的类名
    class_names = [os.path.splitext(os.path.basename(path))[0] for path in file_paths]

    # 检查是否存在具有相同类名的文件
    if len(set(class_names)) != len(class_names):
        # 获取每个类名对应的文件路径列表
        class_paths = {}
        for path in file_paths:
            class_name = os.path.splitext(os.path.basename(path))[0]
            if class_name in class_paths:
                class_paths[class_name].append(path)
            else:
                class_paths[class_name] = [path]

        # 交换具有相同类名的文件路径
        for class_name, paths in class_paths.items():
            if len(paths) > 1:
                for i in range(len(paths) - 1):
                    temp = paths[i]
                    paths[i] = paths[i+1]
                    paths[i+1] = temp

    return file_paths

# 示例用法
file_paths = [
    "/path/to/file1.jpg",
    "/path/to/file2.jpg",
    "/path/to/file3.jpg",
    "/path/to/file4.jpg",
    "/path/to/file5.jpg",
    "/path/to/file6.jpg",
    "/path/to/file7.jpg",
    "/path/to/file8.jpg",
    "/path/to/file9.jpg",
    "/path/to/file10.jpg"
]

swapped_paths = swap_file_paths(file_paths)
print(swapped_paths)