从列表条件中删除某些元素基于另一个列表

list1 = [1, 2, 3, 4, 5, 6, 7, 8, 9]
list2 = [2, 3, 4, 10]

result = [x for x in list1 if x not in list2]
print(result)  # 输出 [1, 5, 6, 7, 8, 9]

list1 = [1, 2, 3, 4, 5, 6, 7, 8, 9]
list2 = [2, 3, 4, 10]

result = list(filter(lambda x: x not in list2, list1))
print(result)  # 输出 [1, 5, 6, 7, 8, 9]