从文件句柄获取文件名？

import os

file_handle = open("example.txt", "r")
file_name = os.path.basename(file_handle.name)
print(file_name)  # 输出：example.txt

import java.nio.file.Path;
import java.nio.file.Paths;

Path filePath = Paths.get("example.txt");
String fileName = filePath.getFileName().toString();
System.out.println(fileName);  // 输出：example.txt

const fs = require('fs');
const path = require('path');

const fileHandle = fs.openSync('example.txt', 'r');
const fileName = path.basename(fs.fstatSync(fileHandle).name);
console.log(fileName);  // 输出：example.txt

using System;
using System.IO;

FileStream fileStream = new FileStream("example.txt", FileMode.Open, FileAccess.Read);
string fileName = Path.GetFileName(fileStream.Name);
Console.WriteLine(fileName);  // 输出：example.txt