从路径中提取最新的文件名

import os

def get_latest_filename(path):
    # 获取指定路径下的所有文件列表
    files = os.listdir(path)
    
    # 筛选出最新的文件
    latest_file = None
    latest_time = 0
    for file in files:
        file_path = os.path.join(path, file)
        if os.path.isfile(file_path):
            file_time = os.path.getmtime(file_path)
            if file_time > latest_time:
                latest_file = file
                latest_time = file_time
    
    # 提取最新文件的文件名
    if latest_file is not None:
        latest_filename = os.path.basename(latest_file)
        return latest_filename
    else:
        return None

# 示例用法
path = '/path/to/files'
latest_filename = get_latest_filename(path)
print("最新的文件名是：", latest_filename)