以特定方式合并字典和字典列表

dict1 = {'a': 1, 'b': 2}
dict2 = {'b': 3, 'c': 4}

merged_dict = {**dict1, **dict2}
print(merged_dict)  # 输出: {'a': 1, 'b': 3, 'c': 4}

list_of_dicts1 = [{'a': 1}, {'b': 2}]
list_of_dicts2 = [{'c': 3}, {'d': 4}]

merged_list_of_dicts = list_of_dicts1 + list_of_dicts2
print(merged_list_of_dicts)  # 输出: [{'a': 1}, {'b': 2}, {'c': 3}, {'d': 4}]

dict1 = {'a': 1, 'b': 2}
list_of_dicts = [{'c': 3}, {'d': 4}]

merged_dict_with_list = {**dict1, **{k: v for d in list_of_dicts for k, v in d.items()}}
print(merged_dict_with_list)  # 输出: {'a': 1, 'b': 2, 'c': 3, 'd': 4}

dict1 = {'a': 1, 'b': 2}
dict2 = {'b': 3, 'c': 4}

merged_dict = {**dict1, **dict2}
print(merged_dict)  # 输出: {'a': 1, 'b': 3, 'c': 4}

def merge_dicts(dict1, dict2):
    merged_dict = dict1.copy()
    for key, value in dict2.items():
        if key in merged_dict:
            merged_dict[key] = [merged_dict[key], value]  # 将值存储为列表
        else:
            merged_dict[key] = value
    return merged_dict

dict1 = {'a': 1, 'b': 2}
dict2 = {'b': 3, 'c': 4}

merged_dict = merge_dicts(dict1, dict2)
print(merged_dict)  # 输出: {'a': 1, 'b': [2, 3], 'c': 4}