我想在sweetalert2的输入中放一个数字掩码,你能帮我吗?我的代码:
onClick(btn) {
let code2_fa = '';
if (JSON.parse(localStorage.getItem('user')).password.two_factors.is_active) {
swal({
title: 'Digite o TOKEN para prosseguir',
imageUrl: './assets/imgs/Authy.svg',
{"error":{"type":"Symfony\\Component\\Debug\\Exception\\FatalErrorException","message":"Class 'Authy_Api' not found","file":"\/home\/vagrant\/Code\/curve\/app\/controllers\/UsersController.php","line":9}}
我将"authy-php":
我使用snap install authy命令安装了authy。当我尝试打开应用程序时,我得到以下错误消息:/snap/authy/6/authy: error loading shared libraries: libX11.so.6: unable to open shared objects file: No such file or directory Ubuntu 20.04.3 LTS
我试图在PHP中为Authy运行一个演示。我已经在Composer中安装了Authy库,所以现在我可以使用以下硬编码值注册用户:
$authy_api = new Authy\AuthyApi('<TESTING API KEY>', 'http://sandbox-api.authy.com'); // actual key omitted -- using the key generated for testing, not the one for production
$user = $authy_api->registerUser(&
目标
我有一个与AWS对话的后端服务,以及一个获得AWS证书的自动化工具。cred-getter启用了MFA (不是我的选择),但我不想键入或复制代码。相反,我想编写一些代码,可以编程方式生成或获取TOTP软令牌,而无需发送文本或呼叫任何人。所以今天我们的工作流程是这样的:
call cred getter from cli => open authy app for totp code => paste into cli
但我希望它看起来像这样:
call my custom cli => it makes a totp code and passes it to cred
我有一个应用程序authy_me,并编写了一个自定义URL
url(r'^login/$', authy_views.log_me_in, name="login")
log_me_in视图包含以下内容:
from django.contrib.auth.forms import AuthenticationForm
from django.contrib.auth.views import login as auth_login
def log_me_in(request):
if request.user.is_staff and not has_