我的网络项目有问题。我在用jackson,序列化有问题。当我试图返回一个hashmap回页面时,这是错误消息:
at com.fasterxml.jackson.databind.ser.std.BeanSerializerBase.serializeFields(BeanSerializerBase.java:644)
at com.fasterxml.jackson.databind.ser.BeanSerializer.serialize(BeanSerializer.java:152)
at com.fasterxml.jackson.databind.ser.BeanProp
我在编写JAX资源时遇到了一个问题。当我将@XmlRootElement添加到JPA实体时,需要使用JAXB和RestEasy将其序列化为XML/JSON。
引发的错误:
Caused by: org.hibernate.LazyInitializationException: failed to lazily initialize a collection of role: pl.salonea.entities.Provider.industries, could not initialize proxy - no Session
at org.hibernate.collection.
首先,当我获得User实体时,我试图防止JSON中的递归。为此,我向我的@JsonIdentityInfo类添加了User注释。它可以像预期的那样用于序列化(当我得到User时),但是对于反序列化(注册User),Jackson返回以下内容:
Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: No Object Id found for an instance of `.entity.User`, to assign to property 'i
我想转换成的对象看起来像这样
public class AdDimension {
private int width;
private int height;
public AdDimension() {
// needed by Jackson
}
public AdDimension(final int width, final int height) {
this.width = width;
this.height = height;
}
..
}
它被用在内部
public clas
我很难将apache管道编译成数据流模板。我使用自定义aws凭据提供程序类从GCP秘密管理器加载基本aws凭据,并在构建模板时看到以下异常:
Caused by: com.fasterxml.jackson.databind.JsonMappingException: Unexpected IOException (of type java.io.IOException): Failed to serialize and deserialize property 'awsCredentialsProvider' with value 'org.example.iot.b
我对Jersey (2.13)有个问题。我想问题与非编组机制有关。我的User实体有一个Role实体的字段集合。当我试图得到它时,我会得到一个错误。
这是我的课
@XmlRootElement(name = "user")
public class User {
private Set<Role> roleSet;
// other fields omitted
@XmlElementWrapper(name = "roles")
@XmlElement(name = "role")
pu
我使用Jackson反序列化xml文件:
public SomeClassDTO deserializeXML(String pathToFile) {
File file = new File(pathToFile);
XmlMapper xmlMapper = new XmlMapper();
String xml = null;
try {
xml = inputStreamToString(new FileInputStream(file));
xml = xml.replaceAll("\\s+",
我能够编写XML文档,但是无法对创建的XML进行反序列化。原来的代码是用Kotlin编写的,但是我已经发布了Java的等价物。
@JacksonXmlRootElement(localName = "assets")
public class Assets {
@JacksonXmlElementWrapper(useWrapping = false)
private Asset[] asset;
public Assets(Asset[] asset) {
this.asset = asset;
}
public A