使用Python根据另一个列表中的值合并列表中的项目

def merge_projects(project_list, value_list, default_value=None):
    merged_list = []
    for value in value_list:
        merged_project = None
        for project in project_list:
            if project['value'] == value:
                merged_project = project.copy()
                merged_project.update({'value': value})
                break
        if merged_project is None:
            if default_value is not None:
                merged_project = {'value': value, 'default': default_value}
            else:
                continue
        merged_list.append(merged_project)
    return merged_list

# 示例数据
project_list = [{'name': 'Project A', 'value': 1}, {'name': 'Project B', 'value': 2}, {'name': 'Project C', 'value': 3}]
value_list = [1, 2, 4, 5]

# 合并项目列表
merged_projects = merge_projects(project_list, value_list, default_value='N/A')

# 打印合并后的项目列表
for project in merged_projects:
    print(project)

{'name': 'Project A', 'value': 1}
{'name': 'Project B', 'value': 2}
{'value': 4, 'default': 'N/A'}
{'value': 5, 'default': 'N/A'}