使用jQuery访问PHP方法

<?php
function sayHello($name) {
    return "Hello, " . $name;
}

if (isset($_POST['name'])) {
    echo sayHello($_POST['name']);
}
?>

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
    $.ajax({
        url: 'process.php',
        type: 'post',
        data: {name: 'John'},
        success: function(response) {
            alert(response);
        }
    });
});
</script>