使用malloc转置数组

#include <stdio.h>
#include <stdlib.h>

int main() {
    int rows, cols;
    printf("Enter the number of rows: ");
    scanf("%d", &rows);
    printf("Enter the number of columns: ");
    scanf("%d", &cols);

    // Dynamically allocate memory for the original array
    int** originalArray = (int**)malloc(rows * sizeof(int*));
    for (int i = 0; i < rows; i++) {
        originalArray[i] = (int*)malloc(cols * sizeof(int));
    }

    // Input elements into the original array
    printf("Enter the elements of the array:\n");
    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < cols; j++) {
            scanf("%d", &originalArray[i][j]);
        }
    }

    // Dynamically allocate memory for the transposed array
    int** transposedArray = (int**)malloc(cols * sizeof(int*));
    for (int i = 0; i < cols; i++) {
        transposedArray[i] = (int*)malloc(rows * sizeof(int));
    }

    // Transpose the original array
    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < cols; j++) {
            transposedArray[j][i] = originalArray[i][j];
        }
    }

    // Print the transposed array
    printf("Transposed array:\n");
    for (int i = 0; i < cols; i++) {
        for (int j = 0; j < rows; j++) {
            printf("%d ", transposedArray[i][j]);
        }
        printf("\n");
    }

    // Free the allocated memory
    for (int i = 0; i < rows; i++) {
        free(originalArray[i]);
    }
    free(originalArray);
    for (int i = 0; i < cols; i++) {
        free(transposedArray[i]);
    }
    free(transposedArray);

    return 0;
}