使用ymd_hms数据计算每小时的最小/最大值

import datetime

# 示例数据，假设为ymd_hms格式的时间数据列表
data = [
    "2022-01-01 12:01:30",
    "2022-01-01 12:05:45",
    "2022-01-01 13:10:20",
    "2022-01-01 13:15:35",
    "2022-01-01 13:20:50",
    "2022-01-01 14:30:10",
    "2022-01-01 14:35:25",
]

# 解析数据并分组
grouped_data = {}
for item in data:
    dt = datetime.datetime.strptime(item, "%Y-%m-%d %H:%M:%S")
    hour = dt.hour
    if hour not in grouped_data:
        grouped_data[hour] = []
    grouped_data[hour].append(dt)

# 计算每小时的最小/最大值
result = {}
for hour, hour_data in grouped_data.items():
    min_value = min(hour_data)
    max_value = max(hour_data)
    result[hour] = {"min": min_value, "max": max_value}

# 输出结果
for hour, values in result.items():
    print(f"Hour {hour}:")
    print(f"  Min: {values['min']}")
    print(f"  Max: {values['max']}")