select
t1.city_name
from
(
select
'全国' as city_name
from
stg.t_vip
union all
select
cc.city_name
from
stg.t_city_config cc
join
stg.t_vip v
on
v.city_id =
我有一张表格,其中包含了全国所有病房的一组不同工作领域的工人人数。如何找到员工数量超过x的病房(跨越所有作业字段)?我当前的查询如下:
SELECT
(SELECT COUNT(1) FROM Table WHERE
(SELECT SUM(working) FROM Table GROUP BY table.ward) > x)
AS working FROM Table;
/*
SELECT countries.name AS country, COUNT(*) AS cities_num
FROM cities
INNER JOIN countries
ON countries.code = cities.country_code
GROUP BY country
ORDER BY cities_num DESC, country
LIMIT 9;
*/
SELECT name AS country,
-- Subquery
(SELECT count(*)
FROM cities
WHERE countries.co
如何将默认状态(例如: QLD改为Quensland)重命名为以下查询的输出?另外,我如何将各州的预测汇总到一个更高的水平(例如:全国)?
SELECT PRODUCT_BK, Month, State, Forecast
FROM
(SELECT * FROM Forecast_Table) t
UNPIVOT
(Forecast FOR State IN (SA_NT, QLD, VIC_TAS, WA, NSW_ACT)) AS fcst
谢谢
这是对的跟进。
如何在下面的group子句中使用OR条件是我的sql查询
SELECT count(id) as num_rows,
(3959 * acos ( cos ( radians(41.766908)) * cos( radians( lat ) ) * cos( radians( lon ) - radians(-81.1526976)) + sin ( radians(41.766908) ) * sin( radians( lat ) ))) AS distance
FROM (`items`)
WHERE `status` = 1
GROUP BY `distance
给定以下类结构
public class Parent
{
public Guid Id { get;
public List<BaseChild> Children { get; set; }
}
public abstract class BaseChild
{
public int Id { get; set; }
public string ChildName { get; set; }
}
public class NormalChild : BaseChild