php $table = 'artwork';
$result = mysql_query("select AID, ThumbFilePath, Title, DisplayOrder from artwork where SCID = $SCID order by DisplayOrder") or die(mysql_error());while($row = mysql_fetch_ar
当没有与SQL查询匹配的行时,Im试图计数有0行的行,但它无论如何返回1行。有人知道我做错了什么吗?$del = mysql_real_escape_string(strip_tags($_GET['del']));
{
$sql6 = "SELECTcount(*) FROM oneliners WHERE id='$del' AND to_user='".&qu
当新行进入mysql数据库时,循环将新行计数为0,当两行进入mysql数据库时,循环将两行计数为1 ??我不知道为什么要使用for loop escape first row count start from second row?,也不知道如何使用数组进行多行会话??where pid='$id'")
or die("Id Problem&q
我试图在查询中应用COUNT(),并且它的工作方式如下:
$sql = "SELECT id, Title, images, recdate, 'item' AS type FROM ads_list WHERE$sql = "SELECT id, Title, images, recdate, 'item' AS type COUNT(*) FROM ads_list WHERE to_days(now())$sql = "SELECT COUNT(*) id, Title, image