我实际上正在用PHP语言开发一个预订系统,我创建了一个脚本来搜索MySql数据库,检查X天是否被占用(或未占用),将未占用的日期存储在一个数组中。之后,我将数组返回给一个打印所有日期的函数,并将这些日期传递给jQuery日期选择器数组变量,这样日期选择器就知道它应该显示哪个日期。问题是,当我打印这个数组时,在开始打印日期之前,它会打印很多新行。
这是在html文件中打印数组的代码:
var datasDisponiveis =
<?php
if (!(isset($_SESSION["dias"]))) {
$_SESSION["dias
您好,有人能告诉我,我应该怎么做:
Error
There is a chance that you may have found a bug in the SQL parser. Please
examine your query closely, and check that the quotes are correct and not mis-matched.
Other possible failure causes may be that you are uploading a file with binary
outside
of a quoted text a
在下面的代码中,我能够更新数据库,但它没有重定向到标题位置中给出的页面,它刷新并显示相同的页面本身,我复制了其他在更新数据库和重定向方面工作良好的代码
<?php
if (isset($_POST['submit']))
{
// get form data, making sure it is valid
$firstname = mysql_real_escape_string(htmlspecialchars($_POST['firstname']));
$link = mysql_connect('www.xxxxxxx.
问候是我目前正在进行的第一次尝试为我的网站开发一个登录。对于这个登录,我使用的是PHP和MySQL。我的问题是我不断收到下面的错误..。我已经用尽了所有的可能性,如何重命名"require_once“输入的知识,但仍然知道运气。
Warning: require_once(C:\Users\Derek\Fall_2013\PS-WebDesign\includes\constants.php) [function.require-once]: failed to open stream: No such file or directory in D:\Hosting\11311638\
在运行我的php代码时,会出现以下错误:
Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/chatvik/public_html/control.php:2) in /home/chatvik/public_html/control.php on line 5
Warning: session_start() [function.session-start]: Cann
我正在尝试运行这里找到的脚本:
bash /path/to/mysql-backup.sh
我收到以下错误:
/path/to/mysql-backup.sh: line 2:
: command not found
/path/to/mysql-backup.sh: line 4:
: command not found
/path/to/mysql-backup.sh: line 8:
: command not found
/path/to/mysql-backup.sh: line 10:
: command not found
/path/to/mysql-backup.sh: li
我有一个将数据存储到mysql中的循环...
/connect to your database
//read your text file into an array, one entry per line
$lines = file('name.txt');
//loop through each website URL you read from the file
foreach ($lines as $name) {
//do some code
//Insert data to MySQL
mysql_query("INSERT INTO ta
当我将"Connection : close“头添加到一个Http请求时,我一直收到一个错误...错误是:
com.mysql.jdbc.MysqlDataTruncation: Data truncation: Data too long for column 'content' at row 1
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3601)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3535)
a
我试图从数组Ar()中删除所有单元格值不等于其中一个值的行。当我把逻辑运算符,不循环,因为某种原因而无限(excel冻结)。相反,如果我想从数组中删除包含值的行,则它可以完美地工作。
问题在网上:
If Not .Cells(i, 10).Value = Ar(j) Then
我的代码:
Sub Tims()
Dim LastRow As Long, LR As Long
Dim i As Long, j As Long
Dim t As Integer
Dim Ar() As String
Worksheets("Start").Ac
我在命令行中输入了以下查询,它起作用了,但当我尝试通过命令@..../filename.sql运行它时,第一个查询起作用了,但第二个不起作用……我不知道为什么。需要帮助。另外,我得到的错误消息是SP2-0042未知命令")“-已忽略行的其余部分
下面是查询
/** Query 1: works through terminal and by calling @.../filename.sql**/
CREATE TABLE CUSTOMER
( cID NUMBER NOT NULL,
firstName VARCHAR2(50) NOT NULL,
lastNa
所以。
#include <mysql/mysql.h>
#include <stdio.h>
int main(){
MYSQL mysql;
MYSQL_ROW row;
MYSQL_RES *result;
unsigned int num_fields;
unsigned int i;
mysql_init(&mysql);
if (!mysql_real_connect(&mysql,"localhost","kevin","****","my_db"