可以模拟c++类中的私有/受保护方法而不继承它吗？

#include <iostream>

class MyClass {
private:
    void privateMethod() {
        std::cout << "Private method called" << std::endl;
    }

protected:
    void protectedMethod() {
        std::cout << "Protected method called" << std::endl;
    }

    friend void friendFunction(MyClass& obj);
    friend class FriendClass;
};

void friendFunction(MyClass& obj) {
    obj.privateMethod();
    obj.protectedMethod();
}

class FriendClass {
public:
    void accessPrivateMethod(MyClass& obj) {
        obj.privateMethod();
    }

    void accessProtectedMethod(MyClass& obj) {
        obj.protectedMethod();
    }
};

int main() {
    MyClass obj;
    friendFunction(obj);

    FriendClass friendObj;
    friendObj.accessPrivateMethod(obj);
    friendObj.accessProtectedMethod(obj);

    return 0;
}