我如何知道哪个函数是构造函数?
在OpenZeppelin实现的MultisigWallet中,OpenZeppelin声称这是构造函数:
/**
* Constructor, sets the owners addresses, number of approvals
required, and daily spending limit
* @param _owners A list of owners.
* @param _required The amount required for a transaction to be
approved.
我有以下表达式:[^(\r\n)]*来识别任何不包含\r\n的文本。但是,当文本包含(或)时,则无法识别。
示例:
"I have following expression to recognize any text."将被确认为OK。
"I have following expression (A) to recognize any text."将不被识别。
因此,我想要全文:"I have following expression (A) to recognize any text."
我正在为身份识别人员创建合同,我需要验证是否有一些合同具有相同的地址、电子邮件或电话号码。
示例:
contract Person {
//date of create
uint public dateCreate;
//name of person
string public name;
//variables to be validates
string public email;
string public phone;
// constructor
function Person(string _name, string _email, string _phone) publi
<?php
interface iFoo {
public function print(): iFoo;
}
class Foo implements iFoo {
public function print(): iFoo {
return $this;
}
public function chain(): iFoo {
return $this;
}
}
$foo = new Foo();
$foo->print()
->chain() // Method 'chain