在不计算负数的情况下，如何找出一个数字在列表中出现了多少次？

def count_occurrences(number, lst):
    count = 0
    for num in lst:
        if num == number:
            count += 1
    return count

# 示例用法
numbers = [1, 2, 3, 4, 2, 5, 2]
target_number = 2
occurrences = count_occurrences(target_number, numbers)
print(f"The number {target_number} appears {occurrences} times in the list.")