在使用panResponder时，如何在扁平列表中拖放单个项目？

import React, { Component } from 'react';
import { View, Text, PanResponder } from 'react-native';

class ListItem extends Component {
  constructor(props) {
    super(props);
    this.state = {
      panResponder: PanResponder.create({
        onStartShouldSetPanResponder: () => true,
        onMoveShouldSetPanResponder: () => true,
        onPanResponderMove: (evt, gestureState) => {
          // 处理拖动过程中的逻辑
          const { dx, dy } = gestureState;
          // 更新列表项的样式
          this.setState({
            style: {
              transform: [{ translateX: dx }, { translateY: dy }],
            },
          });
        },
        onPanResponderRelease: (evt, gestureState) => {
          // 处理拖放结束后的逻辑
          const { dx, dy } = gestureState;
          // 判断是否放置在某个特定区域内
          if (dx > 100 && dy > 100) {
            // 执行相应的操作
          }
          // 重置列表项的样式
          this.setState({
            style: {
              transform: [{ translateX: 0 }, { translateY: 0 }],
            },
          });
        },
      }),
      style: {},
    };
  }

  render() {
    return (
      <View
        style={[styles.listItem, this.state.style]}
        {...this.state.panResponder.panHandlers}
      >
        <Text>列表项</Text>
      </View>
    );
  }
}

class FlatListWithDragDrop extends Component {
  render() {
    return (
      <View>
        <ListItem />
        <ListItem />
        <ListItem />
      </View>
    );
  }
}

const styles = {
  listItem: {
    width: 100,
    height: 100,
    backgroundColor: 'gray',
    margin: 10,
  },
};

export default FlatListWithDragDrop;