在日期范围数组中查找“漏洞”(间隙)

import datetime

def find_date_gaps(date_array):
    sorted_dates = sorted(date_array)
    gaps = []
    
    for i in range(len(sorted_dates) - 1):
        current_date = sorted_dates[i]
        next_date = sorted_dates[i + 1]
        
        if (next_date - current_date).days > 1:
            gap_start = current_date + datetime.timedelta(days=1)
            gap_end = next_date - datetime.timedelta(days=1)
            gaps.append((gap_start, gap_end))
    
    return gaps

# 示例日期范围数组
date_array = [datetime.date(2022, 1, 1), datetime.date(2022, 1, 3), datetime.date(2022, 1, 4), datetime.date(2022, 1, 7)]

# 查找日期范围数组中的间隙
gaps = find_date_gaps(date_array)

# 打印结果
for gap in gaps:
    print("间隙起始日期:", gap[0])
    print("间隙结束日期:", gap[1])
    print("---")

间隙起始日期: 2022-01-02
间隙结束日期: 2022-01-02
---
间隙起始日期: 2022-01-05
间隙结束日期: 2022-01-06
---