在更短的时间内从一个列表中删除另一个列表中的所有值(优化时间)

def remove_values(main_list, values_to_remove):
    # 将需要删除的值转换为集合
    set_to_remove = set(values_to_remove)
    
    # 使用列表推导式过滤掉需要删除的值
    result_list = [item for item in main_list if item not in set_to_remove]
    
    return result_list

# 示例使用
main_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
values_to_remove = [3, 6, 9]

result = remove_values(main_list, values_to_remove)
print(result)  # 输出: [1, 2, 4, 5, 7, 8, 10]

def remove_values_generator(main_list, values_to_remove):
    set_to_remove = set(values_to_remove)
    for item in main_list:
        if item not in set_to_remove:
            yield item

# 示例使用
result_generator = remove_values_generator(main_list, values_to_remove)
for item in result_generator:
    print(item)  # 输出: 1 2 4 5 7 8 10