final public class ImmutableWithObject {
final Object obj;
final List myList;
ImmutableWithObject(Object obj1, List list)
{
this.obj = obj1;
this.myList = ((List) ((ArrayList) list).clone());
}
public Object getObj() {
return this.obj;
}
pu
我在几个地方读过,比如关于“访问链接”和“显示方法”,用于查找非局部变量。但是,似乎没有人触及到复杂的情况,比如在JavaScript中,您可以在函数内部拥有函数,并从函数返回这些函数,同时保持这些函数的“内部范围”。
这里是一个复杂的嵌套函数。
let m = foo()
m()
m()
function foo() {
let x = 10
function bar() {
let y = 2 ** x
function hello() {
let z = 30
function another() {
// PL
我想更好地理解以下Rust代码背后的语义:
use std::thread;
fn main() {
let immutable = "I am not mutable";
let mut mutable = "I am mutable";
let handle1 = thread::spawn(move || {
println!("Thread 1 says: {}", immutable);
});
let handle2 = thread::spawn(move || {
给定一个使用回调将事件传递给库用户的库(例如GUI库),我将如何继续在程序中进行适当的更改?例如:
// so I have this `obj` I want to modify when the user clicks buttons
// in the GUI
let same_action = move |_| {
// modify obj in several ways, e.g. obj.text = "Modified"
obj.text = "Modified";
}
// --> I had to move `obj` abo
第一次经历了一个闭包例子,但是我很难把我的头绕在控制流上。
public class TestLambdaClosure {
public static void main(String[] args) {
int a= 10;
int b=20;
//doProcess(a, i-> System.out.println(i+b));
doProcess(a, new Process() {
@Override
public void process(int i