在C函数指针中传递更多参数

#include<stdio.h>

typedef struct {
    int arg1;
    int arg2;
    int arg3;
} Args;

void my_function(Args args) {
    printf("arg1: %d, arg2: %d, arg3: %d\n", args.arg1, args.arg2, args.arg3);
}

int main() {
    Args args = {1, 2, 3};
    void (*function_pointer)(Args) = my_function;
    function_pointer(args);
    return 0;
}

#include<stdio.h>

typedef void (*Callback)(int, int, int);

void my_function(int arg1, int arg2, int arg3) {
    printf("arg1: %d, arg2: %d, arg3: %d\n", arg1, arg2, arg3);
}

void call_function_with_args(Callback callback, int arg1, int arg2, int arg3) {
    callback(arg1, arg2, arg3);
}

int main() {
    call_function_with_args(my_function, 1, 2, 3);
    return 0;
}