我想在链表二叉搜索树中找出给定节点到根的距离。我有下面的代码来计算树的高度(root.getHeightN()),从根到叶,但我现在需要的是从叶到根。
public int getHeightN(){
int l, r;
if(this.left == null){
l = 0;
}else{
l = this.left.getHeightN();
}
根据的说法,树中的所有东西都是节点。
树中使用的术语
Root – The top node in a tree.
Parent – The converse notion of child.
Siblings – Nodes with the same parent.
Descendant – a node reachable by repeated proceeding from parent to child.
Ancestor – a node reachable by repeated proceeding from child to parent.
Leaf – a node wi
description: A new Flutter application.
# The following line prevents the package from being accidentally published to
# pub.dev using `pub publish`. This is preferred for private packages.
publish_to: 'none' # Remove this line if you wish to publish to pub.dev
# The following defines the
在Visual Studio Code v1.46.1中运行应用程序时出现主要错误 FAILURE: Build failed with an exception.
* What went wrong:
Execution failed for task ':app:cleanMergeDebugAssets'.
> Unable to delete directory 'E:\ACNO\Flutter\jots_mobile\build\app\intermediates\merged_assets\debug\out'
Failed to
在堆排序中,当在for循环中重新排列数组时,为什么我们需要i= n/2 -1,并且我检查了n/2,它也像预期的那样工作。
// Build heap (rearrange array)
for (int i = n / 2 - 1; i >= 0; i--)
heapify(arr, n, i);
取而代之的是,我使用了如下代码:
// Build heap (rearrange array)
for (int i = n / 2; i >= 0; i--)
heapify(arr, n, i);
下面是完整的程序,
/
如何才能看到导致小部件不断传播小部件树的原因?我正在使用提供程序包,并且遇到了小部件不断堆叠的问题--例如,如果我在主页中添加了一个print语句:
@override
Widget build(BuildContext context) {
print("Home");
然后,在浏览应用程序一段时间后,如果我清除调试控制台并加载主页或它下面的任何屏幕,我将得到多个"Home“打印,即:
flutter: Home
flutter: Home
flutter: Home
flutter: Home
flutter: Home
flutter: Home
我越