在Go中对具有交替内容类型的XML元素进行解组

package main

import (
    "encoding/xml"
    "fmt"
    "log"
)

type Person struct {
    XMLName xml.Name `xml:"person"`
    Name    string   `xml:"name"`
    Age     int      `xml:"age"`
    Email   string   `xml:"email"`
}

func main() {
    xmlData := `
        <person>
            <name>John Doe</name>
            <age>30</age>
            <email>john.doe@example.com</email>
        </person>
    `

    var person Person
    err := xml.Unmarshal([]byte(xmlData), &person)
    if err != nil {
        log.Fatal(err)
    }

    fmt.Println("Name:", person.Name)
    fmt.Println("Age:", person.Age)
    fmt.Println("Email:", person.Email)
}