在Java中,您如何编写可能抛出异常的Iterable的等价物？

import java.util.Iterator;

public class ExceptionIterable<T> implements Iterable<T> {
    private Iterable<T> iterable;
    private ExceptionHandler<T> exceptionHandler;

    public ExceptionIterable(Iterable<T> iterable, ExceptionHandler<T> exceptionHandler) {
        this.iterable = iterable;
        this.exceptionHandler = exceptionHandler;
    }

    @Override
    public Iterator<T> iterator() {
        return new ExceptionIterator<>(iterable.iterator(), exceptionHandler);
    }

    public interface ExceptionHandler<T> {
        void handle(T item, Exception exception);
    }

    private static class ExceptionIterator<T> implements Iterator<T> {
        private Iterator<T> iterator;
        private ExceptionHandler<T> exceptionHandler;

        public ExceptionIterator(Iterator<T> iterator, ExceptionHandler<T> exceptionHandler) {
            this.iterator = iterator;
            this.exceptionHandler = exceptionHandler;
        }

        @Override
        public boolean hasNext() {
            return iterator.hasNext();
        }

        @Override
        public T next() {
            T item = null;
            try {
                item = iterator.next();
            } catch (Exception e) {
                exceptionHandler.handle(item, e);
            }
            return item;
        }
    }
}

List<Integer> numbers = Arrays.asList(1, 2, 3, 4, 5);
ExceptionIterable<Integer> exceptionIterable = new ExceptionIterable<>(numbers, (item, exception) -> {
    System.out.println("Exception occurred while processing item " + item + ": " + exception.getMessage());
});

for (Integer number : exceptionIterable) {
    // Process the number
}