在Mongodb/Java中，如何在sortByCount操作后返回所有字段而不仅仅是id和count？

import org.springframework.data.mongodb.core.aggregation.Aggregation;
import org.springframework.data.mongodb.core.aggregation.Fields;
import org.springframework.data.mongodb.core.aggregation.LookupOperation;
import org.springframework.data.mongodb.core.aggregation.TypedAggregation;
import org.springframework.data.mongodb.core.query.Criteria;

TypedAggregation aggregation = Aggregation.newAggregation(
    // 关联其他集合
    Aggregation.lookup("otherCollection", "fieldToJoin", "fieldToReturn", "asField"),
    // 分组并排序
    Aggregation.group("groupField").count().as("count").first("otherField").as("otherField"),
    Aggregation.sort(Sort.Direction.DESC, "count"),
    // 选择需要返回的字段
    Aggregation.project("groupField", "count", "otherField")
);

List<YourResultClass> results = mongoTemplate.aggregate(aggregation, "yourCollection", YourResultClass.class).getMappedResults();