我希望我的PHP文件传递:mysite.com/?id=ABC123abc到mysite.com/ABC123abc$request = parse_url($_SERVER['REQUEST_URI']);$_GET['id'] = $path; //my server returns error 404 - not found
在谷
URL结构是mywebsite.com/giveaway/giveaway.php?id=(any number),我希望将该动态URL更改为静态/友好的URL mywebsite.com/giveaway/name-of-giveaway-corresponding-to-id。在根文件夹中找到的.htaccess文件中,我有以下内容:
R