在Python内部函数中传递变量的差异

count = 0

def increment():
    global count
    count += 1

increment()
print(count)  # 输出: 1

def outer():
    count = 0

    def increment():
        nonlocal count
        count += 1
    
    increment()
    print(count)  # 输出: 1

outer()

my_list = [1, 2, 3]

def modify_list():
    my_list.append(4)

modify_list()
print(my_list)  # 输出: [1, 2, 3, 4]

my_string = "Hello"

def modify_string():
    my_string = "World"
    return my_string

my_string = modify_string()
print(my_string)  # 输出: World

my_list = [1, 2, 3]

def modify_list(lst):
    lst.append(4)

modify_list(my_list)
print(my_list)  # 输出: [1, 2, 3, 4]

my_string = "Hello"

def modify_string(s):
    s = "World"
    return s

my_string = modify_string(my_string)
print(my_string)  # 输出: World