在df列中每第n个字符后插入换行符

import pandas as pd

# 假设df是一个包含需要处理的数据的DataFrame对象，列名为'column_name'
df['column_name'] = df['column_name'].astype(str)  # 将列转换为字符串类型

n = 3  # 每第n个字符后插入换行符

for i in range(len(df['column_name'])):
    string = df['column_name'][i]
    new_string = '\n'.join([string[j:j+n] for j in range(0, len(string), n)])
    df['column_name'][i] = new_string

# 打印处理后的DataFrame
print(df)